2x+3y=60 solve for x...
x=(60-3y)/2
p=xy^3, using x from above:
p=y^3(60-3y)/2
p=(60y^3-3y^4)/2
dp/dy=(180y^2-12y^3)/2
dp/dy=90y^2-6y^2
dp/dy=0 when:
90y^2-6y^3=0
6y^2(15-y)=0, we know y>0 so
y=15, since x=(60-3y)/2
x=7.5
(We solved it this way because otherwise you get quartic equations and cubic derivatives, yuck :P)
Answer: x + 2x + x-40 = 180
First angle= 55º
Second angle= 110º
Third angle= 15º
Step-by-step explanation: The sum of the angles of a triangle is 180º
Take the values given and use x as the unknown first angle. then create terms for the other two angles based on that:
The second angle of a triangle is double the first angle becomes 2x
The third angle is 40 less than the first angle becomes x-40
x + 2x + x-40 = 180 Solve by adding like terms . x + 2x + x = 4x
4x -40 = 180 Add 40 to both sides to "cancel" the -40 on the left
4x + 40 -40 = 180 + 40 becomes
4x = 220 Divide both sides by 4 to "cancel" the 4 on the left side
4x/4 = 220/4
x = 55 This is the first angle. Substitute 55 for the "x" in the original terms
2(55) = 110 The second angle
(55) -40 = 15 the third angle
An exterior angle of a triangle is equal to the sum of the opposite interior angles.
⇢∠V + ∠T = ∠x
⇢53° + 103° = 156°
⇢∠VUX = 156°
Hence , option b is the correct answer.
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Answer:
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