Answer: sin = ±
Step-by-step explanation:
We very well know that,
cos2A=1−2sin²A
⟹ sinA = ±
As required, set A = & cos a=
,thus we get
sin =±
∴ sin =±
= ±
since ,360° < <450°
,180° < <225°
Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.
hope it helped!
Answer:
a₇ = 2.375
Step-by-step explanation:
There is a common ratio r between consecutive terms, that is
r = =
=
= -
This indicates the sequence is geometric with nth term
= a₁
where a₁ is the first term and r the common ratio
Here a₁ = 152 and r = - , then
= 152
, so
a₇ = 152 = 152 ×
= 2.375
Answer:
f(x) = -1.18056x² +9.55556x -12.4604
Step-by-step explanation:
As required by the problem statement, technology was used to find the polynomial function that passes through the given points. The coefficients shown above are rounded to 6 significant figures. The exact coefficients appear to be ...
f(x) = (-1 13/72)x² +(9 5/9)x -(12 221/480)
