Answer:
B
Step-by-step explanation:
the decay will cause loss so it's the function B
Based on the given values above, here is the solution to find if how many ants there will be after 10 weeks and 20 weeks.
Since the population increases by 12%. we need to get 12% of the population every week.
500 x .12 = 60.
1st week = 560
2nd week = 627.2
3rd week = 702. 46
4th week = 786.76
5th week = 881. 17
6th week = 986.91
7th week= 1,105.34
8th week= 1,237.98
9th week= 1, 386.54
10th week = 1, 552.92
11th week = 1,739.27
12th week = 1,947.98
13th week= 2,181.74
14th week=2, 443.55
15th week = 2,736.76
16th week = 3, 065. 17
17th week = 3,432.99
18th week= 3,844.95
19th week= 4,306.34
20th week = 4,823.10
Therefore, after 10 weeks, there will be 1,553 ants and after 20 weeks, there will be 4,823 ants.
Answer:
BD=AD-AB=6-4=2
Step-by-step explanation:
You have a line segment AD that measures 6 units
AB is part of it and it is 4 units
There is only one part left of AD and it is BD so you just find what's left of 6 if 4 is already spoken for.
Answer:
Slope: 2
Step-by-step explanation:
Taking any two points on the slope: (0,1) & (1,3)
where (0,1) is (x1,y1) and (1,3) is (x2,y2)
Substituting into the slope formula as below:
= (3-1)/(1-0)
= 2/1
= 2
Hence, the slope is 2
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Answer:
Step-by-step explanation:
Start by factoring out a 5:
We need to find two integers that have a product of 12, and a sum of -7:
(-3)(-4)=12
-3-4=-7
We can split -7x into -3x and -4x
Factor each half separately:
![5[x(x-3)-4(x-3)]](https://tex.z-dn.net/?f=5%5Bx%28x-3%29-4%28x-3%29%5D)
Since x and -4 are both being multiplied by x-3, we can combine them:
