A=s2 solve for s literal equations
1 answer:
Assuming the is 
you would need to take the square root of both sides. Normally, we insert +or- when using square root to solve.
Considering this formula is for the area of a square and sides are a length and can't be represented by a negative number we would not need the -.
Therefore
but I would speak with my instructor about the issue.
Considering this formula is for the area of a square and sides are a length and can't be represented by a negative number we would not need the -.
Therefore
but I would speak with my instructor about the issue.
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Answer:
a. 0.313% (0.003134842261), b. 237.79 days (237.788095878)
Step-by-step explanation:
In this case, the length of pregnancies is a normally distributed variable, with a mean of 266 days, and a standard deviation of 15 days.
A graph showing the distribution, with regions of interest for the answer, is presented below.
<h3>First Part: Find the probability of a pregnancy lasting 307 days or longer.</h3>To answer the question regarding <em>the probability of a pregnancy lasting 307 days or longer</em>, it is necessary to calculate what the cumulative probability distribution value is at 307 days. By the way, according to the graph below, 307 days are quite far from the population mean (266 days).
Using the function <em>normaldist(266,15).cdf(307)</em>, from free Desmos software on Internet, we find that, at this length (307 days), the sum of all probabilities for all cases at this value is 99.69% (0.996865157739).
Considering that the total area of the curve is 1, then <em>the probability of pregnancy lasting 307 days or longer</em> is 1 - 0.996865157739 or 0.003134842261 (or 0.00313), approximately 0.313%, a very low probabilty.
This probability is showed as the "light blue" region at the right extreme of the graph.
<h3>Second Part: Find the length that separates premature babies from those who are not premature.</h3>To find the length that separates premature babies from those who are not premature, it is a question about <em>find the days related with the probability of 3% (or 0.03)</em> to find such premature babies. So, it is a question of finding a percentile (or 100-quantiles): given the cumulative normal distribution curve, what is the value (length of pregnancies) that represents this 3%.
Using the function <em>quantile(normaldist(266,15), 0.03)</em>, from free Desmos software on Internet, we obtained a value of 237.79 days (237.788095878) for the length of pregnacies of premature babies. In other words, those babies whose mothers have a length of pregnancy <em>lower</em> than 237.79 days are considered premature, or this is "the length that separates premature babies from those who are not premature".
The area below 237.79 days is the blue shaded region in the graph below, at the left extreme of it.
