Answer:
The total surface area of this square pyramid is 
Step-by-step explanation:
we know that
The surface area of a square pyramid is equal to
![SA=b^{2} +4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have
----> the length side of the square base
----> the height of the triangular faces
substitute the values
![SA=9^{2} +4[\frac{1}{2}(9)(12)]=297\ mm^{2}](https://tex.z-dn.net/?f=SA%3D9%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%289%29%2812%29%5D%3D297%5C%20mm%5E%7B2%7D)
Answer:
In(8x)=[In]8 + [In]x
Step-by-step explanation:
By product rule:
![In(8x)=[In]8 + [In]x](https://tex.z-dn.net/?f=In%288x%29%3D%5BIn%5D8%20%2B%20%5BIn%5Dx)
Answer
![12b^{2} \sqrt[3]{2a}](https://tex.z-dn.net/?f=12b%5E%7B2%7D%20%5Csqrt%5B3%5D%7B2a%7D)
Step-by-step explanation:
A) V = P + PRT
<span>
V=P(1+RT)
P=A/(1+RT)
P = 6000 / (1 + .08 X 7)
P = 6000 / 1.56
P = $3,846.15</span>
I wish I knew but same profile pic pog