Question

Y=x² – 8x + 16So right now I'm trying to figure out the inverse relation ​

Answer 1

Answer:

The inverse relation is:

$y=4 \pm \sqrt{x}$

Step-by-step explanation:

We need to solve for x.

Useful formula: (x-y)^2=x^2-2xy+y^2.

$y=x^2-8x+16$

$y=(x-4)^2$

Now, take the square root of both sides:

$\pm \sqrt{y}=x-4$

Add 4 on both sides:

$4 \pm \sqrt{y}=x$

Interchange x and y:

$4 \pm \sqrt{x}=y$

The inverse relation is:

$y=4 \pm \sqrt{x}$