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2 years ago

The three inside angels (a,b,c) of a right angled triangle are in the ratio 7:18:11 the smallest is 35. Work out angle A,B,C

Mathematics

1 answer:

rusak2 [61]2 years ago

4 0

The smallest angle is a which is 35 and from 7 to 35 it X5 so times 18 and 11 by 5 as well which comes to the ratio 35:90:55 , you can tell this is right because angles in a triangle add up to 180 , 35+90+55 =180

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Suppose x is a real number and epsilon > 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in

kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let $y\in (x-\epsilon,x+\epsilon)$ . then we have that $x-\epsilon$ . Hence, it makes sense to define the positive number delta as $\delta=\min\{x+\epsilon-y,y-(x-\epsilon)\}$ (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that $(y-\delta,y+\delta)\subseteq (x-\epsilon,x+\epsilon)$ , and if we prove this, we are done. To prove it, let $z\in (y-\delta,y+\delta)$ , then $y-\delta$ . First, $\delta \leq y-(x-\epsilon)$ then $-\delta \geq -y+x-\epsilon$ hence $z>y-\delta \geq x-\epsilon$

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3 0

3 years ago

Could somebody help me im slow sorry

Mars2501 [29]

Answer:

I'd say multiply the numerators then the denominators and at the end simplify at least thats how I multiply fractions :)

8 0

2 years ago

A committee of four students is being randomly selected from a group of twenty students. How many combinations of four students

Cloud [144]

Answer:

4,845

Step-by-step explanation:

Hope this helps:)

7 0

2 years ago

How do I find the area

inn [45]

Wasssaa,

Steps:

To find the area of a triangle you multiply the base times the height, in this case the is (19m)
and the height is (11m), after you multipy those numbers you divide by (2)
$(19m \times 11m) \div 2$
$\frac{209 }{2}$

Answer:
$104.5sq \: m$
Hope this helped you
:D

8 0

2 years ago

How do you simplify that question? For algebra 1.

motikmotik

$\left( \sqrt{x^{-3}} \right)^5 = \left( \sqrt{ \frac{1}{x^3} } \right)^5= \frac{1}{ (\sqrt{x^3})^5 } = \frac{1}{ \sqrt{x^{15}} } = \frac{1}{x^7 \sqrt{x} }$

<span>Explanation for the last step:</span>
$\sqrt{x^{15}}= \sqrt{x^{14}*x}= \sqrt{x^{14}}* \sqrt{x} =x^{ \frac{14}{2} }* \sqrt{x} =x^7 \sqrt{x}$

7 0

2 years ago