1. so it has to have every x is one y and every y has one x
graph them
we see that the only ones that are one to one are the first one, the 2nd one and the 4th one
2.
solve for x and replace with f⁻¹(x) and y with x
minus 8 and cube both sides
(y-8)³=x-2
add 2
(y-8)³+2=x
replace
f⁻¹(x)=(x-8)³+2
first one
3.
this is a one to one function because theer is no vertical line that could intersect the graph more than once
ah, I see, you're program has a different one to one definition, no horizontal or vertical line can cross, lemme edit te first question again
answer is 2nd option
4. a neat trick is this:
the domain of f(x) is the range of f⁻¹(x)
the range of f(x) is the domain of f⁻¹(x)
the domain of f(x)=1/(3x+2)
hmm, can't divide by 0 so set denomenator to 0
3x+2=0
3x=-2
x=-2/3
domain is all real numbers except -2/3
(-infinity,-2/3)U(-2/3,infinity)
that's the range of f⁻¹(x)
range
ok, hmm, range is from positive initny to 0 then from 0 to positive inifnty, not including 0
so the domain of f⁻¹(x) is (-∞,0)U(0,∞)
range of f⁻¹(x) is (-∞,-2/3)U(-2/3,∞)
first option
Given:
Amount in the savings account = 4300
Each week, Raul pays the dog sitter 30 from his savings account.
To find:
The function, f(x), that is equal to the amount of money in the account after Raul pays the dog sitter each week.
Solution:
Let x be the number of weeks.
Raul pays the dog sitter in 1 week = 30
Raul pays the dog sitter in x week = 30x
Remaining amount = Initial amount - Amount he pays the dog sitter
Therefore, the required function is .
Answer:
The area of triangle is 48.
Step-by-step explanation:
Given:
The vertices of triangle are (0,0),(12,0),(2,8).
Now, to find the area of triangle.
So, the coordinates of triangle are:
.
Now, to get the area of triangle we put formula:
Therefore, the area of triangle is 48.
Arctan(3/5) ≈ 0.5 . . . . . radians
.. ≈ 31.0 . . . . . . . . . . . . . degrees
Answer:
-12x^4y^6z^3
Step-by-step explanation: