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creativ13 [48]
3 years ago
8

Find the 81st term of the arithmetic sequence -10, -25, -40

Mathematics
2 answers:
nadezda [96]3 years ago
6 0

Answer:

-1210

Step-by-step explanation:

The nth term is -10-(15(n-1)) so

-10-(15(80)=

-10-1200=

-1210

Maurinko [17]3 years ago
5 0

Answer:

5 - (N x 15)

81 x 15 = 1215

5-1215=-1210

-1210 should be the 81st term

Step-by-step explanation:

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Step-by-step explanation:

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\mathrm{Multiply\:and\:divide\:by\:10\:for\:every\:number\:after\:the\:decimal\:point.}

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\mathrm{The\:GCD\:of\:}a,\:b\mathrm{\:is\:the\:largest\:positive\:number\:that\:divides\:both\:}a\mathrm{\:and\:}b\mathrm{\:without\:a\:remainder}

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2,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

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=\frac{8\cdot \:27}{8\cdot \:125}

\mathrm{Cancel\:the\:common\:factor:}\:8

=\frac{27}{125}

Hence, the correct answer is =\frac{27}{125}

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