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Dennis_Churaev [7]
3 years ago
12

Tomorrow is my exam Wow C no only​

Mathematics
1 answer:
ozzi3 years ago
8 0

Answer:

e. 3

f. (2x-3)(2x+3)

Step-by-step explanation:

e. 1+2=3

f. (2x)²-(3)² {a²-b²}=(a-b)(a+b)

(2x-3)(2x+3)

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Step-by-step explanation:

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Suppose a square ABCD has a side length of 1 unit. The arcs BD and AC are circular arcs with centers at A and D, respectively. F
Likurg_2 [28]

Answer:

1-\frac{\sqrt{3} }{4}-\frac{\pi}{6}

Step-by-step explanation:

The missing figure is shown in the attachment

The area of the shaded region = Area of Square - (Area of sector AOB + Area of equilateral  triangle BOC + Area of sector COD)

Area of Sector AOB=Area of Sector COD=\frac{30}{360}*\pi*1^2=\frac{\pi}{12}

Area of equilateral triangle =\frac{1}{2}*r*\frac{\sqrt{3} }{2}*r=  \frac{1}{2}*1*\frac{\sqrt{3} }{2}*=\frac{\sqrt{3} }{4}

Area of shade region =1^2-\frac{\sqrt{3} }{4}-\frac{\pi}{12}*2

1-\frac{\sqrt{3} }{4}-\frac{\pi}{6}

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