1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ycow [4]
3 years ago
12

What is the missing term to make these ratios equal 21 : 3 = :9

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
7 0

Answer:

63:9 is equal to 21:3

Step-by-step explanation:

Zielflug [23.3K]3 years ago
4 0
63. The ratio 63:9 is equal to 21:3 because 3x3 is 9 and 21x3 is 63
You might be interested in
In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini
svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2

The augmented matrix is

\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]

The reduction of this matrix to row-echelon form is outlined below.

R_2\rightarrow R_2-R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]

R_3\rightarrow R_3-2R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]

R_3\rightarrow R_3-R_2

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]

The last row determines, if there are solutions or not. To be consistent, we must have k such that

k^2-k-2=0

\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2

Case k = −1:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]

This gives the infinite many solution.

5 0
3 years ago
A class of 118 students went on a field trip. They took 10 vehicles, some vans (x) and some buses (y). Find the number of vans a
I am Lyosha [343]

Answer:

Solve for x+y=10

               6x+35y=118

Step-by-step explanation:

I would solve it for you but my calculator isn't working rn. You could also use a picture calculator and it will give you a more in depth explanation. Hope this helps!

7 0
3 years ago
The point G(6,4) is rotated 180° clockwise around the origin. What
siniylev [52]

Answer:

Step-by-step explanation:

when (x,y) is rotated through 180 then new coordinates are (-x',-y')

G(6,4)→G'(-6,-4)

5 0
3 years ago
The diagram below show the dimensions of a container of sand that is shaped like a rectangular prism . The container is filled u
monitta

Answer:

Its B

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Find the slope of each line 2-3. please help thank you.
atroni [7]
2)
(-3, 3) (2,0)
slope = (3-0)/(-3-2) = -3/5

3)
y = 3
so slope = 0
7 0
3 years ago
Other questions:
  • Add three fraction together to get a whole number using the numbers 1-9 only once
    10·1 answer
  • How many times can 1 go into 0
    15·2 answers
  • I have 23 hundreds,7 tens and 10 ones. what number am i ?
    10·1 answer
  • Four less than half a number is 15. Find a number.
    14·2 answers
  • If $2887.51 is 60%, What is 100%?
    9·1 answer
  • Monique bought a shirt for $22.80 during a 30% off sale. How much dose the shirt cost when it is not on sale
    10·2 answers
  • How would I do this<br> Need help
    5·2 answers
  • Write each phrase as an algebraic expression<br><br> Two times n squared added to nine
    5·2 answers
  • Ignore the one I put :&gt;
    9·1 answer
  • I WILL GIVE BRAINLIEST !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!