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Bingel [31]
3 years ago
12

What is the measure of angle c?

Mathematics
2 answers:
vfiekz [6]3 years ago
8 0

Answer:

B 103°

Step-by-step explanation:

A triangle always adds up to 180° so you add measurement B and A together the subtract it from 180° to find C

Darina [25.2K]3 years ago
7 0

Answer: B) 103

Step-by-step explanation:

A triangle’s angles always adds up to 180 degrees. If the first two sides are 34 and 43, which added together equals 77, then subtract 180 and 77 to get the third angle, which is 103

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Which of the following statements must be true, given that AABC= AXYZ,
sattari [20]

Answer:

B. m ∠Z = 32°

Given:

Δ ABC ≅ Δ XYZ

m ∠ C = 32°

When 2 triangles are congruent we can say that all side of 1 triangle are equal to corresponding sides of other triangle.

Side AB= Side XY And Side BC = Side YZ and side AC = side XZ

Also,

When 2 triangles are congruent we can say measure of all angles of 1 triangle are equal to measures corresponding angles of other triangle.

m ∠A = m ∠X and m ∠B = m∠Y and m ∠C = m ∠Z

m ∠ C = 32° hence m ∠ Z = 32

3 0
3 years ago
Find x <br><br> H,I x+12<br> I,J 16+x<br> H,J 20
AlladinOne [14]

Answer:

x=-4

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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An artist used silver wire to make a square that has a perimeter of 40 inches. She then used copper wire to make the largest cir
Serhud [2]

Answer:

The artist used 8.6\ in more of silver wire

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

we know that

The Perimeter of the square is equal to

P=4a

where

a is the length side of the square

P=40\ in

so

40=4a

a=10\ in

so

Each side of the square has a length of 10 in

step 2

Find the circumference of the circle

The diameter of the circle is equal to the length of the side of  the square

The circumference is equal to

C=\pi D

we have

D=10\ in

substitute

C=(3.14)(10)=31.4\ in

step 3

Find the difference

40\ in-31.4\ in=8.6\ in

4 0
4 years ago
<img src="https://tex.z-dn.net/?f=cos%20%5B%20arctan%28%5Cfrac%7B12%7D%7B5%7D%29%20-%20arcsin%20%28%5Cfrac%7B-3%7D%7B5%7D%29%5D"
qwelly [4]

Answer: -16/65

Step-by-step explanation:

Drawing the right triangle (as attached) gives us that \arctan \left(\frac{12}{5} \right)=\arcsin \left(\frac{12}{13} \right)

Also, -\arcsin \left(-\frac{3}{5} \right)=\arcsin \left(\frac{3}{5} \right)

This means our original expression is equal to:

\cos \left[\arcsin \left(\frac{12}{13} \right)+\arcsin \left(\frac{3}{5} \right) \right]

Using the cosine addition formula, which states \cos(a+b)=\cos a \cos b-\sin a \sin b, we get this itself is equal to:

\cos \left(\arcsin \left(\frac{12}{13} \right) \right)\cos \left(\arcsin \left(\frac{3}{5} \right)\right)-\sin \left(\arcsin \left(\frac{12}{13} \right) \right)\sin \left(\arcsin \left(\frac{3}{5} \right)\right)

Since \sin^{2} \theta+\cos^{2} \theta=1, we know that:

\sin^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)+\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\\frac{144}{169} +\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{25}{169}\\\\cos \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{5}{13}

Similarly, cos(arcsin(3/5))=4/5.

This means the given expression is equal to:

\left(\frac{5}{13} \right) \left(\frac{4}{5} \right)-\left(\frac{12}{13} \right) \left(\frac{3}{5} \right)\\\\\frac{20}{65}-\frac{36}{65}=\boxed{-\frac{16}{65}}

3 0
2 years ago
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