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natta225 [31]
3 years ago
15

What is the relationship between the ratios? 48/72 and 6/9

Mathematics
2 answers:
lord [1]3 years ago
6 0
42 : 72 = 6 : 9

is <span>FALSE

Hope it helped : )
</span>
frutty [35]3 years ago
4 0

I took the test and it said the answer was (proportional)


I hope I help


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yes because she would only use 96 gallons of gas and still have 4 gallons left.


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4 years ago
Trevor has four boxes of raisins to share equally among himself and two friends how many boxes of Raisin would each person recei
Wittaler [7]
1. box of raisin and there will be one left over
6 0
3 years ago
Read 2 more answers
How? (2x^2 - 3x - 4)(x + 7)<br>​
lidiya [134]

Answer:

2 {x}^{3}  +  11{x}^{2}  - 25x - 28

Step-by-step explanation:

Using foil method, Multiply the first term

2 {x}^{2}  \times x = 2 {x}^{3}

Next, Multiply the Outer term in each parenthesis. (2x^2 and 7

2 {x}^{2}  \times 7 = 14 {x}^{2}

2 {x}^{2}  \times 7 = 14 {x}^{2}  \:  \:  \: 3x \times  - x =  - 3x

Then, Multiply the Inner Terms (-3x,-4,7) in each parenthesis

- 3x \times 7 =  - 21x

- 4 \times x =  - 4x

Then multiply the last term (-4 and 7).

- 4 \times 7 =  - 28

Combine it you have

2 {x}^{3}  + 14 {x}^{2}   - 3 {x}^{2}  - 21x - 4x - 28

which simplify to

2 {x}^{3}  + 11 {x}^{2}  - 25x - 28

3 0
3 years ago
Tyler has 30 marbles 40% of his marbles are blue how many of his marbles are blue
rewona [7]

Answer:

12 marbles are blue.

Step-by-step explanation:

3 x 4 = 12, so 40 % of 30 is 12.

6 0
3 years ago
Determine en donde la funcion dada es creciente,concava hacia riba y concava hacia abajo. y= x3–3x–1
Minchanka [31]

Answer:

Es creciente en los siguientes intervalos: [-\infty,-1] U [1,\infty]

Es concavo hacia abajo en el intervalo: [-\infty,0)

Es concavo hacia arriba en el intervalo: (0,\infty]

Step-by-step explanation:

Sea la función:

f(x)=x^{3}-3x-1

Para determinar el intervalo de crecimeinto debes determinar la primer derivada de la función (f'(x)). El intervalo donde f'(x) > 0 es creciente.

La derivada de f(x) es:

f'(x)=3x^{2}-3

Entonces es creciente en los siguientes intervalos:

[-\infty,-1] U [1,\infty]    

Ahora para determinar la concavidad debemos determinar la segunda derivada de la función (f''(x)). Si f''(x) > 0 la función es concava hacia arriba, si f''(x) < 0 la funcion es concava hacia abajo.

La segunda derivada de f(x) es:

f''(x)=6x        

Por lo tanto:

Es concavo hacia abajo en el intervalo: [-\infty,0)

Es concavo hacia arriba en el intervalo: (0,\infty]

Espero te haya ayudado!

8 0
3 years ago
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