Answer:
21 is correct answer.
Step-by-step explanation:
Given: AM || ML || CK || DJ and AB=BC=CD
To Determine: JM=?
Construction: Join AK which intersect BL at E ( In Attachment)
Calculation:
In ΔAKC , B is mid point of AC and BE || CK
Therefore, E is also mid point of AK. By converge of mid point theorem.
AE=EK
In ΔAKM , E is mid point of AK and LE || AM
Therefore, L is also mid point of MK. By converge of mid point theorem.
ML=LK
Similarly, We can prove LK=KJ
Where, ML=LK=KJ=7
JM=ML+LK+KJ
JM=7+7+7
JM=21
Thus, 21 is correct answer.