The answer is B because all prime numbers are multiplied by one.
The given polynomial is not a prime polynomial.
Given the polynomials, we have to choose the polynomial which is prime.
A polynomial with integer coefficients that cannot be factored into lower degree polynomials is Prime polynomials.
![7x^2-35x+2x-10](https://tex.z-dn.net/?f=7x%5E2-35x%2B2x-10)
![7x^2-33x-10](https://tex.z-dn.net/?f=7x%5E2-33x-10)
![\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}](https://tex.z-dn.net/?f=%5Cmathrm%7BFor%5C%3Aa%5C%3Aquadratic%5C%3Aequation%5C%3Aof%5C%3Athe%5C%3Aform%5C%3A%7Dax%5E2%2Bbx%2Bc%3D0%5Cmathrm%7B%5C%3Athe%5C%3Asolutions%5C%3Aare%5C%3A%7D)
<h3>What is the formula for the quadratic roots?</h3>
![\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cquad%20x_%7B1%2C%5C%3A2%7D%3D%5Cfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
![\mathrm{For\:}\quad a=7,\:b=-33,\:c=-10](https://tex.z-dn.net/?f=%5Cmathrm%7BFor%5C%3A%7D%5Cquad%20a%3D7%2C%5C%3Ab%3D-33%2C%5C%3Ac%3D-10)
![x_{1,\:2}=\frac{-\left(-33\right)\pm \sqrt{\left(-33\right)^2-4\cdot \:7\left(-10\right)}}{2\cdot \:7}](https://tex.z-dn.net/?f=x_%7B1%2C%5C%3A2%7D%3D%5Cfrac%7B-%5Cleft%28-33%5Cright%29%5Cpm%20%5Csqrt%7B%5Cleft%28-33%5Cright%29%5E2-4%5Ccdot%20%5C%3A7%5Cleft%28-10%5Cright%29%7D%7D%7B2%5Ccdot%20%5C%3A7%7D)
![x_{1,\:2}=\frac{-\left(-33\right)\pm \sqrt{\left(-33\right)^2-4\cdot \:7\left(-10\right)}}{2\cdot \:7}](https://tex.z-dn.net/?f=x_%7B1%2C%5C%3A2%7D%3D%5Cfrac%7B-%5Cleft%28-33%5Cright%29%5Cpm%20%5Csqrt%7B%5Cleft%28-33%5Cright%29%5E2-4%5Ccdot%20%5C%3A7%5Cleft%28-10%5Cright%29%7D%7D%7B2%5Ccdot%20%5C%3A7%7D)
![x_{1,\:2}=\frac{-\left(-33\right)\pm \:37}{2\cdot \:7}](https://tex.z-dn.net/?f=x_%7B1%2C%5C%3A2%7D%3D%5Cfrac%7B-%5Cleft%28-33%5Cright%29%5Cpm%20%5C%3A37%7D%7B2%5Ccdot%20%5C%3A7%7D)
![x_1=\frac{-\left(-33\right)+37}{2\cdot \:7},\:x_2=\frac{-\left(-33\right)-37}{2\cdot \:7}](https://tex.z-dn.net/?f=x_1%3D%5Cfrac%7B-%5Cleft%28-33%5Cright%29%2B37%7D%7B2%5Ccdot%20%5C%3A7%7D%2C%5C%3Ax_2%3D%5Cfrac%7B-%5Cleft%28-33%5Cright%29-37%7D%7B2%5Ccdot%20%5C%3A7%7D)
![x=5,\:x=-\frac{2}{7}](https://tex.z-dn.net/?f=x%3D5%2C%5C%3Ax%3D-%5Cfrac%7B2%7D%7B7%7D)
Therefore the factor is (x-5) and (7x+2).
can be factored
∴ not a prime polynomial.
To learn more about the prime polynomial visit:
brainly.com/question/26388060
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15/16 should be the right answer b/c 1/4= 4/16
Answer: The function is: f(x) = 2*(x +1)
Step-by-step explanation:
This can be translated to:
"write an equation of a function where a whole number x corresponds to the next number to x"
the next whole number to x is x+1., and we want the double of that.
Then we have that our function is:
f(x) = 2*(x +1)
Now we can do a little table of it:
f(0) = 2*(0 + 1) = 2
f(1) = 2*(1 + 1) = 4
f(2) = 2*(2+ 1) = 6