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Sidana [21]
3 years ago
7

PLEASE HELP DUE TONIGHT

Mathematics
1 answer:
Alika [10]3 years ago
4 0

Answer:

The answer should be 20,000 feet

Step-by-step explanation:

sin 0 =opposite/hypotenuse

sin 30 = AB/AC

sin 30 = 10000/c

c= 10000/sin 30

c=10000/1/2

c=20,000 feet

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A student got a summer job at an electronics store. the student is given two different compensation plans. plan A pays a weekly
kykrilka [37]
They will make the same amount after 10 phones sold. Before that Plan A is the better plan. After 10, Plan B is the better plan. 

You can find the point of intersection by modelling the two equations and setting them equal to each other. If x is equal to phones sold:

250 + 25x = 50x
250 = 25x
10 = x

Therefore, you make the same at 10 phones. 
4 0
3 years ago
When 1480 is divided into 12 equal parts, the remainder is 4. What is a correct way to write the quotient? (3 points)
In-s [12.5K]

Answer:

Depending on what type of math class you are in, or how your teacher taught it, it could be either 12 R:4 or 12 + 1/370.

Step-by-step explanation:

Remainders can be written in two ways, R: [remainder] or the whole number quotient + [remainder number]/[dividend]. For this problem you would have to simplify 4/1480 to 1/370 because 1480/4 equals 370. So, your final answer would be 12 + 1/370 or 12 R:4.

3 0
3 years ago
Help me asap!!!! please
Lubov Fominskaja [6]

Answer:

x = 3 should be the answer

Step-by-step explanation:

y is not graphed so y isn't part of the equation while x is so its X = K (K being the number that it goes up on) same thing applies to y if its horizontal then the equation is Y = K)

6 0
2 years ago
Write and equation for the shift of the parent graph y=1/x
SashulF [63]
You can think of this equation as \bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}

and thus apply the transformations to it as such

\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

1)  D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7
7 0
3 years ago
A garrison of 120 people had provisions for 30 days. If 20 people leave the garrison after 10 days, how long does the remaining
stiv31 [10]

Answer:

24 days

total units = 120* 30 = 3600

used after 10 days =  120*10 = 1200

remaining units after 10 days = 3600-1200 = 2400

2400/100 people = 24 days that the provisions will last

Step-by-step explanation:

6 0
3 years ago
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