The maximum profit, as taught in calculus, can be determined when you equate the first derivative of the function to zero. So,
P' = 300 + 0
Hence, the maximum profit is 300.
I'm not sure about the vertices, though. Anyhow, I hope I was able to help you. Have a good day.
Answer:
x^2 + 6x
Step-by-step explanation:
A = lw
l = x + 6
w = x
Plug in values
(x + 6) × x = x^2 + 6x
232.47
184.50 × 26% = 47.97 +184.50= 232.47
Step-by-step explanation:
Answer:
X ≤ 2
Step-by-step explanation:
x/(3 - 2) ≤ 2
3-2 = 1
x/1 ≤ 2
X ≤ 2
Answer:
-48-12g
Step-by-step explanation:
Use the distributive property to get your answer