How do you solve (3c)³ - (c - 4d)²; c = -2 AND d = 5

1 answer:

algol132 years ago

8 0

You just plug in the values.

[3*(-2)]^3 - (-2 - 4*5)^2

(-6)^3 - ( - 2 - 20)^2

-216 - (-22)^2

-216 - (484)

-216 - 484

-700

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