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Vitek1552 [10]
3 years ago
6

When you don’t know the answer on a multiple choice questions, it is generally best to:

Mathematics
1 answer:
kipiarov [429]3 years ago
5 0
B , go with your first guest
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Do u agree?I m not pretty sure
nika2105 [10]
It looks correct to me :)
6 0
3 years ago
Read 2 more answers
Which of the following is an integer?<br> 0.5<br> 1<br> 3/2
Vinil7 [7]
Yeah the answer is one
3 0
3 years ago
Read 2 more answers
Find the probalitywhen a pair of 8-sided fair die is rolled and the sum of the roll is greater than 9
Tresset [83]

Odd Numbers : 1, 3, 5, 7 = 4 numbers

Total numbers on 8-sided die = 8

P(rolling an odd number) = 4/8 = 1/2

Die is defined as ceasing to live, exist, or disappear. An example of this is pulling a plant out of the ground by its roots. An example of death is when a person's heart stops and the brain stops working. stop living; dead out.

Use ``die of'' when someone dies of direct causes. We use ``die of'' when someone died from an indirect cause. "die by" is used when someone dies from something. He died of cancer.

Learn more about  die  here

brainly.com/question/14192140

#SPJ4

4 0
1 year ago
(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each
Leviafan [203]

Following are the solution parts for the given question:

For question A:

\to (n) = 16

\to (\bar{X}) = 410

\to (\sigma) = 40

In the given question, we calculate 90\% of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}

\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\

Using the t table we calculate t_{ \frac{\alpha}{2}} = 1.753  When 90\% of the confidence interval:

\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53

So 90\% confidence interval for the mean weight of shipped homemade candies is between 392.47\ \ and\ \ 427.53.

For question B:

\to (n) = 500

\to (X) = 155

\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31

Here we need to calculate 90\% confidence interval for the true proportion of all college students who own a car which can be calculated as

\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}

\to C.I= 0.90

\to (\alpha) = 0.10

\to \frac{\alpha}{2} = 0.05

Using the Z-table we found Z_{\frac{\alpha}{2}} = 1.645

therefore 90\% the confidence interval for the genuine proportion of college students who possess a car is

\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344

So 90\% the confidence interval for the genuine proportion of college students who possess a car is between 0.28 \ and\ 0.34.

For question C:

  • In question A, We are  90\% certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
  • In question B, We are  90\% positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:  

brainly.in/question/16329412

7 0
2 years ago
Evaluate A2 for A = -4
vekshin1
Hello there!

Evaluate a²  for a = -4

The first step we need to do is replace a by -4

So we have (-4)²

Now what you have realize is that we need to multiply -4 by itself twice.

So it should looks like this:

-4 * -4

The rules says that when we have minus * minus, the answer is positive.

So we have -4 * -4 = 16

Answer: 16

I hope this helps!

Please let us know if you have other questions.

#Garebear
8 0
3 years ago
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