Answer:
50
Step-by-step explanation:
trust me
Based on the SAS congruence criterion, the statement that best describes Angie's statement is:
Two triangles having two pairs of congruent sides and a pair of congruent angles do not necessarily meet the SAS congruence criterion, therefore Angie is incorrect.
<h3 /><h3>What is congruency?</h3>
The Side-Angle-Side Congruence Theorem (SAS) defines two triangles to be congruent to each other if the included angle and two sides of one is congruent to the included angle and corresponding two sides of the other triangle.
An included angle is found between two sides that are under consideration.
See image attached below that demonstrates two triangles that are congruent by the SAS Congruence Theorem.
Thus, two triangles having two pairs of corresponding sides and one pair of corresponding angles that are congruent to each other is not enough justification for proving that the two triangles are congruent based on the SAS Congruence Theorem.
The one pair of corresponding angles that are congruent MUST be "INCLUDED ANGLES".
Therefore, based on the SAS congruence criterion, the statement that best describes Angie's statement is:
Two triangles having two pairs of congruent sides and a pair of congruent angles do not necessarily meet the SAS congruence criterion, therefore Angie is incorrect.
Learn more about congruency at
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Answer:
The graph in the attached figure
Step-by-step explanation:
we have
----> inequality A
solve for y


The solution of the inequality A is the shaded area above the dashed line
The slope of the dashed line is positive
The y-intercept is the point 
The x-intercept is the point 
----> inequality B
The solution of the inequality B is the shaded area below the dashed line
The slope of the dashed line is positive
The y-intercept is the point 
The x-intercept is the point 
Using a graphing tool
The solution of the system of inequalities in the attached figure
Answer:
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum (or "no absolute maximum")
Step-by-step explanation:
There will be extremes at the ends of the domain interval, and at turning points where the first derivative is zero.
The derivative is ...
h'(t) = 24t^2 -48t = 24t(t -2)
This has zeros at t=0 and t=2, so that is where extremes will be located.
We can determine relative and absolute extrema by evaluating the function at the interval ends and at the turning points.
h(-1) = 8(-1)²(-1-3) = -32
h(0) = 8(0)(0-3) = 0
h(2) = 8(2²)(2 -3) = -32
h(∞) = 8(∞)³ = ∞
The absolute minimum is -32, found at t=-1 and at t=2. The absolute maximum is ∞, found at t→∞. The relative maximum is 0, found at t=0.
The extrema are ...
- (-1, -32) absolute minimum
- (0, 0) relative maximum
- (2, -32) absolute minimum
- (+∞, +∞) absolute maximum
_____
Normally, we would not list (∞, ∞) as being an absolute maximum, because it is not a specific value at a specific point. Rather, we might say there is no absolute maximum.