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ICE Princess25 [194]
3 years ago
6

IM SOOOO STUCKKKK HELLPPPPPPPPPPP!!

Mathematics
2 answers:
KonstantinChe [14]3 years ago
3 0

Answer:

18

Step-by-step explanation:

x² = 16² + 30² - 2(16)(30)cos 30°

x² = 256 + 900 - 960(0.866)

x² = 1156 - 831.36

x² = 324.64

x = 18.02

Approx. 18

Please mark my answer as brainliest

kykrilka [37]3 years ago
3 0

Answer:

18.01

Step-by-step explanation:

c^2=a^2+b^2-2abcos 30=

   = 16^2+30^2-2(16)(30)(cos30)             cos30=0.866

   = 1156-480√3 = 324.6156

c=√324.6156=18.01

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Which point on the graph represents the y-intercept?
babunello [35]

Answer:

Step-by-step explanation:

It would be point B. Since y-intercept is when the x is at 0, the answer would be point B.

5 0
2 years ago
Work out the area of this trapezium
skelet666 [1.2K]

Step-by-step explanation:

Area = ½ × b × h

= ½ × (7.9 + 10.8) × 6.2

= ½ × 18.7 × 6.2

= ½ × 115.94

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So, the area of that trapezium is 57.97 cm²

<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>

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3 years ago
If 3x+2=11<br> then x= ?
leonid [27]

Answer:

X=3

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
The area of a rectangle is represented by the function A = n^3 - 6n^2 - 8n + 48.
aliya0001 [1]

Answer:

P = 2(n - 6) + 2(n^2 - 8)

Step-by-step explanation:

Remembering that Area = Length times Width, we factor the given function

A = n^3 - 6n^2 - 8n + 48 in the expectation that the resulting factors represent the length and width respectively:

A = n^3 - 6n^2 - 8n + 48 factors as follows:

A = n^2(n - 6) - 8(n - 6), or A = (n - 6)(n^2 - 8)

We can label '(n - 6)' "width" and '(n^2 - 8'

length.

Then the perimeter, P, of the rectangle is P = 2(length) + 2(width). which works out here to:

P = 2(n - 6) + 2(n^2 - 8)

5 0
3 years ago
Help me please<br>help me please​
Nikolay [14]

Answer:

1 second

Step-by-step explanation:

s=-5\\u=0\\v=\\a=-10\\t=t

\begin{aligned}\textsf{Using} \quad s & =ut+\dfrac12at^2\\ \implies -5 & =(0)t+\dfrac12(-10)t^2\\ -5 & = -5t^2\\ t^2& = 1\\ t & = \pm\sqrt{1}\\ t & = 1\: \sf s\end{aligned}

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3 years ago
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