Answer:
The quantity of water in the tank after 15 days is 1610.0 gallons OR 1.61 × 10³ gallons.
Step-by-step explanation:
The amount of water in the tank after 15 days is given by the series
910+(−710)+810+(−610)+⋯+310+(−110)+210
From the series, we can observe that, if water is added for a particular day then water will be drained the following day.
Also, for a day when water is to be added, the quantity to be added will be 100 gallon lesser than the quantity that was last added. Likewise, for a day when water is to be drained, the quantity to be drained will be 100 gallons lesser than the quantity that was last drained.
Hence, we can complete the series thus:
910+(−710)+810+(−610)+710(-510)+610(-410)+510(-310)+410(-210)+310+(−110)+210
To evaluate this, we get
910-710+810-610+710-510+610-410+510-310+410-210+310-110+210
= 1610.0 gallons
Hence, the quantity of water in the tank after 15 days is 1610 gallons OR 1.61 × 10³ gallons.
9514 1404 393
Answer:
x = 22.5°
Step-by-step explanation:
The interior angle at E is (180 -4x), the supplement of the exterior angle there, 4x. The sum of angles 2x and (180-4x) will be equal to 6x, because alternate interior angles at transversal BE are congruent:
2x +(180 -4x) = 6x
180 = 8x . . . . . . . add 2x and simplify
22.5 = x . . . . . . . divide by 8
The value of x is 22.5°.
Answer:
Step-by-step explanation:
1a. 25/50 =x/100
25*100= 2500/50= 50
A= 50%
1b. 35/40 = x/100
35*100= 3500/40= 87.5
A=87.5%
2a. 15/20= x/100
20*5= 100; 15*5= 75
A=75%
2b. 25/70= x/100
25*100= 2500/70= 35.71
A=35.71
3a. 15/80= x/100
15*100= 1500/80=18.75
A=18.75%
3b. 30/60= x/100
30/60= 1/2;1/2=0.5;0.5= 50%
A=50%
4a. 70/80 =x/100
70*100=7000/80 =87.5
A=87.5
4b.30/60 = 50% ( same as question #3b)
Answer:
Approximately 4,000 times
Step-by-step explanation:
If you're flipping a coin to get 4 heads out of 10 and you times it by 10,000 then you would have a probable win rate of 4,000.
Answer:
(8,1)
Step-by-step explanation: