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3 years ago

A cone-shaped ten has a diameter of 12 ft and a height of 6 ft

1 answer:

3 0

$\bf \textit{volume of a cone}=V=\cfrac{\pi r^2 h}{3}\qquad 
\begin{cases}
r=radius=\frac{diameter}{2}\\
h=height\\
--------------\\
height=6\\
diameter=12\\
radius=\frac{diameter}{2}=\frac{12}{2}=6
\end{cases}$

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maks197457 [2]

Answer:

b. A = 71.6°; C = 45.40°; b =15.0

Step-by-step explanation:

The missing values can be found with the help of the Law of Cosine and properties of triangles:

Side b (Law of Cosine)

$b = \sqrt{a^{2}+c^{2}-2\cdot a \cdot c \cdot \cos B}$

$b = \sqrt{16^{2}+12^{2}-2\cdot (16)\cdot (12) \cdot \cos 63^{\circ}}$

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Angle A (Law of Cosine)

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$\cos A = - \frac{16^{2}-15.022^{2}-12^{2}}{2\cdot (15.022)\cdot (12)}$

$\cos A = 0.315$

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$C = 45.361^{\circ}$

Hence, the right answer is B.

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