First number is a and second one is 2a+4
a(2a+4)=48
a(a+2)=24
a^2+2a-24=0
(a+6)(a-4)=0
the question says a is negative so a=-6 b=-8
Yes, they are independent event such that occurring the first event “choosing a sophomore” does not affect the probability of occurring the second event <span>“choosing someone who replied ‘Yes’”</span><span />
Answer:
See below
Step-by-step explanation:
1) x=2-1
x=1
2) (x+1)(x+1)=2(x+1)
3) 10x-20 -11 = 4+3x
10x-3x=20+11+4
7x=35
x=5
When you solve, a quadratic formula is set up as ax^2+bx+c so in this scenario a is 1, b is -1 and c is -6.
-(-1)+- √- 1^2-4(1)(-1)/2(1) is
1+/-√1+4/2 equals -2 and 3 making the answer c
Step-by-step explanation:
