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butalik [34]
3 years ago
10

50 points!!! Need It ASAP

Mathematics
2 answers:
stira [4]3 years ago
7 0

Answer:

Last option

Step-by-step explanation:

Alex17521 [72]3 years ago
6 0

The last option :) Ask if explanation needed

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This should be easy for you <br> Please help me
Alik [6]

Explanation:

a. The line joining the midpoints of the parallel bases is perpendicular to both of them. It is the line of symmetry for the trapezoid. This means the angles and sides on one side of that line of symmetry are congruent to the corresponding angles and sides on the other side of the line. The diagonals are the same length.

__

b. We observe that adjacent pairs of points have the same x-coordinate, so are on vertical lines, which have undefined slope. KN is a segment of the line x=1; LM is a segment of the line x=3. If the trapezoid is isosceles, the midpoints of these segments will be on a horizontal line. The midpoint of KN is at y=(3-2)/2 = 1/2. The midpoint of LM is at y=(1+0)/2 = 1/2. These points are on the same horizontal line, so the trapezoid <em>is isosceles</em>.

__

c. We observed in part (b) that the parallel sides are KN and LM. The coordinate difference between K and L is (1, 3) -(3, 1) = (-2, 2). That is, segment KL is the hypotenuse of an isosceles right triangle with side lengths 2, so the lengths of KL and MN are both 2√2.

_____

For part (c), we used the shortcut that the hypotenuse of an isosceles right triangle is √2 times the leg length.

7 0
3 years ago
If i was born april 16th 1991 how old would i be?
Aleksandr [31]
You would be 26 im pretty sure
8 0
3 years ago
Read 2 more answers
Am i correct? calculus
Advocard [28]
Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer.  That matters because the derivative of a constant is zero.

now, those are the values when the rocket is 30 feet up above.

\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y&#10;\\\\\\&#10;\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}&#10;\\\\\\&#10;\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\&#10;-------------------------------\\\\&#10;

\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}&#10;\\\\\\&#10;\cfrac{d\theta }{dt}=\cfrac{11}{75}

8 0
3 years ago
The distance of one light-year is approximately 9,500,000,000,000 kilometers. What is this distance in scientific notation?
zhenek [66]

Answer:

9.5*10^12 km

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Brainlyst for the best answer thank you!
densk [106]
Answer: B

We all know that area= LxW
The width that is being shown is 8ft. The length is 20ft. Therefore, you multiply 8 x 20 which gives you 160ft squared. Hope this this helps :)
6 0
3 years ago
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