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olasank [31]
2 years ago
13

What is the area and perimeter of this rectangle? please help me! i put this at 14 points

Mathematics
2 answers:
Lorico [155]2 years ago
6 0

Answer:

first find the length of each side using the pythagorean theorem, then multiply the length of any two connected sides for the area. add the length of all four sides to get the perimeter

Step-by-step explanation:

attashe74 [19]2 years ago
4 0

Answer:

not sure of this answer, but -1215 as area,  perimiter 24???

Step-by-step explanation:

I dont know how to do this math i just multiplied the number points and added them T_T im in middle school T_T

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Please help I’ll give brainliest and 20 extra points!
Anastasy [175]

Answer:

<em>42/63 = .6 repeating</em>

<em>30/38 = .625</em>

<em>36/60 = .6</em>

<em>57/90 = .63 repeating</em>

Step-by-step explanation:

Nd if I'm wrong then the 2nd nd 3rd one are switched

8 0
3 years ago
Can someone pls help me? I don’t really get this
Marta_Voda [28]
What is it? The question?
8 0
3 years ago
Can someone please help ASAP
Talja [164]
Answer:
6

how:
add up all the numbers the divide by the amount of numbers given.

Use:
First, I added all the numbers up and got 48.
Next, I divided by 8.
Last, I did 42 divided by 8 and got 6.
The mean is 6.
6 0
3 years ago
Read 2 more answers
Find an equation for the nth term of the arithmetic sequence. -15, -6, 3, 12, ...
Mariulka [41]

Answer: t_{n}=-15+9(n-1)

Step-by-step explanation:

The formula for finding the nth term of an arithmetic sequence is given as:

t_{n}=a+(n-1)d

a = first term = -15

d = common difference = -6 - (-15) = 9

n = number of terms

substituting into the formula , we have :

t_{n} = -15+(n-1)9

t_{n}=-15+9(n-1)

5 0
3 years ago
With a little care, you can find the median and the quartiles from the histogram. what are these numbers? you can also find the
coldgirl [10]

Complete Question

The histogram from this question is shown on the first uploaded image

Answer:

The first quartile is  1st Q = 19^{th} girl (subject ) = 1 \serving\ of\ fruit\ per\ day

The median is   Median  = 38 ^{th} \ girl (subject) =  2 \serving\ of\ fruit\ per\ day

The third quartile  is 3rd Q =  56^{th} \  girl (subject) = 4 \serving\ of\ fruit\ per\ day  

The  mean is  \= x = 2.62

Step-by-step explanation:

From the question we are told that

   The total  number of girls is n =  74

Generally the median is mathematically represented as

       Median  =  \frac{\frac{n}{2}  +[ \frac{n}{2} + 1]  }{2}

So

          Median  =  \frac{\frac{74}{2}  +[ \frac{74}{2} + 1]  }{2}

=>         Median  =  \frac{37  +38 }{2}

=>         Median  =37.5 \  girl    

From the histogram 37.5 \approx 38^{th} \ girl fall under 2 fruits per day

Generally the first quartile is mathematically represented as

      1st \ Q =  \frac{\frac{n}{4} + [\frac{n}{4} + 1]  }{2}

=>    1st \ Q =  \frac{\frac{74}{4} + [\frac{74}{4} + 1]  }{2}

=>     1st \ Q = 19 \  girl

From the histogram 19^{th}girl fall under 1 fruit per day

 Generally the third quartile is mathematically represented as

     3rd\  Q =  \frac{\frac{n}{2}  + n }{2}

=>    3rd\  Q =  \frac{\frac{74}{2}  + 74 }{2}

=>    3rd\  Q =  55.5

From the histogram 55.5 \approx 56^{th} \ girl fall under 4 fruits per day

Generally from the histogram table the frequency  [number of subjects (girls) ]  and the servings of fruit per day can be represented as

                                                                                                               Total

x(servings per day )        0     1     2     3     4     5    6     7      8    

f (number of subjects )   15    11   15     11    8     5    3     3      3    \sum f  =  74

xf                                       0    11    30   33   32  25   18   21     24    \sum xf =  194

Generally the mean is mathematically represented as

      \= x = \frac{1}{ \sum f}  * [\sum xf]

=>     \= x = \frac{1}{ 74}  *194

=>      \= x = 2.62

4 0
3 years ago
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