4.
h(f(x)=h(2x-1)=
(2x-1)^2+1=
4x²-4x+1+1=
4x²-4x+2
5.
f(f(x))=2(2x-1)-1=4x-2-1=4x-3
6.
f o g (x)=f(g(x))
h o g (x)=h(g(x))=
(3x)^2+1=
9x²+1
Answer:

Step-by-step explanation:
- Simplify




- Find the additive inverse of
by using its property - <em>"Sum of a number & its additive inverse is always zero". </em>Assume that 'x' is an additive inverse of
.


- Simplify




- Now, find the product of
& 


Tge answer is 598,802.395 because if you put it into tge calculator you should get this answer
Answer:


Step-by-step explanation:
Given

Required
Find all product of real values that satisfy the equation

Cross multiply:


Subtract 7 from both sides


Reorder

Multiply through by -1

The above represents a quadratic equation and as such could take either of the following conditions.
(1) No real roots:
This possibility does not apply in this case as such, would not be considered.
(2) One real root
This is true if

For a quadratic equation

By comparison with 



Substitute these values in 


Add 56 to both sides


Divide through by 4

Take square roots


Hence, the possible values of r are:
or 
and the product is:

