4X-4Y>28
X-Y>7 both side divide by 4
For 1 year, the house appreciates $4375 (3.5% of 125,000). Therefore after 10 years, $4375(10) = $43750. $125,000+ $43750 = $168,750.
$ 105
Suave gets $ 35 a day, but he realized he got $ 7 for every table he waited for.
= $ 35/7
= 5 .... He waited for 5 tables
which gets $ 7 for any table worth it
= 15 tables × $ 7
= $ 105
Answer:
a)
b) The probability for the couple to be very confident that they will get at least one boy in 6 children is
%
Step-by-step explanation:
The probability of having a boy or girl is ![0.5](https://tex.z-dn.net/?f=0.5)
A couple plans to have 6 children
Probability of having at least one male child
![1- (0.5)^6\\](https://tex.z-dn.net/?f=1-%20%280.5%29%5E6%5C%5C)
On solving the above term, we get -
![1- (\frac{1}{2})^6\\= 1-\frac{1}{64}\\ = \frac{63}{64}](https://tex.z-dn.net/?f=1-%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E6%5C%5C%3D%201-%5Cfrac%7B1%7D%7B64%7D%5C%5C%20%3D%20%5Cfrac%7B63%7D%7B64%7D)
The probability for the couple to be very confident that they will get at least one boy in 6 children is
![\frac{63}{64}* 100\\ = 98.43](https://tex.z-dn.net/?f=%5Cfrac%7B63%7D%7B64%7D%2A%20100%5C%5C%20%3D%2098.43)
Thus, the probability is very high
where is the picture of the box and whisker plot I don't see nothin'