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mart [117]
4 years ago
8

When supply and demand meet at the equilibrium point, then prices in the market will?

Business
2 answers:
ololo11 [35]4 years ago
6 0
Supply is the total quantity of a specific good and service that are available to the consumers in the market while demand is the amount or quantity of goods and services that consumers are able and willing to buy in the market. Equilibrium point is the point at which the demand curve meets the supply curve such that the quantity demanded is equal to the quantity supplied. Therefore, at this point prices in the market will be at equilibrium (equilibrium price) which are not too high or too low. 
Verizon [17]4 years ago
6 0

Answer:

The price in the market will be EQUILIBRIUM.

Explanation:

Market equilibrium is a condition in the market where demand of goods in the market is equal to supply of goods. The prices in the market will be equilibrium.

Equilibrium price is the price in the market where the quantity of goods supplied is equal to the quantity of goods that it is been demanded.

It is the point where the demand curve intersect with the supply curve in the market.

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The ALG Manufacturing Company has gathered the following information for the month of September:• 6,000 units in the beginning W
mars1129 [50]

Answer:

C. 66,000

Explanation:

Ending Work in Process (WIP) = Beginning Work in Process + Units Started into Production - Units Completed and Transferred

Ending WIP = 6,000 * 100% + 60,000 - 50,000 = 16,000

Equivalent Units of Production (EUP) = Units Completed + Units Ending WIP x % of conversion

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3 years ago
A manufacturer estimates that its product can be produced at a total cost of C(x) = 50,000 + 100x + x3 dollars. If the manufactu
timofeeve [1]

Answer:

The level of production x that will maximize the profit is: 22,966

Explanation:

C(x) = 50,000 + 100x + x³

R(x) = 3400x

P(x) = R(x) - C(x)

      = 3400x - [50,000 + 100x + x³]

      = 3400x - 50,000 - 100x - x³

      = 3300x - 50,000 - x³   .................... (A)

P'(x) = 3300(1) - 0 - 3x²

       = 3300 - 3x²

At a critical point, P'(x) = 0

∴   0 = 3300 - 3x²

  3x² = 3300

    x² = 1100

     x = ± \sqrt{1100}

P"(x) = -6x

P(\sqrt{1100}) = -6 (\sqrt{1100})   < 0

by second derivative, 'P' max at    x = \sqrt{1100} = 33.17 (rounds)

since x =  \sqrt{1100} ,

recall that P(x) = 3300x - 50,000 - x³ from equation (A)

Therefore, Maximum Profit

P(\sqrt{1100}) = 3300\sqrt{1100} - 50000 - \sqrt{1100} ^{3}

              = 3300(33.17) - 50,000 - 33.17³

              = 109461 -50,000 - 36495.26

              = 22,965.74

Maximum profit is 22,966 to the nearest whole number

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3 years ago
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