$\bf \stackrel{1}{i^0}\cdot \stackrel{i}{i^1}\cdot \stackrel{-1}{i^2}\cdot \stackrel{-i}{i^3}\cdot \stackrel{1}{i^4}\implies i\cdot i\cdot 1\implies i^2\implies -1$

8 0

3 years ago

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The points plotted below are on the graph of a polynomial. In what range of x-values must the polynomial have a root?

joja [24]

Actually, I think the question should be, "In what range(s) of x-values must there be a root of the POLYNOMIAL?" Unless you are working with some real strange maths, polynomials are smooth and continuous. If you drew a smooth and continuous line through the points in the graph, where would the line have to cross the x-axis?

6 0

3 years ago