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3 years ago

Use properties of equality to solve the equation for w. You must show your work. 2(w+3) = −2(w−21)

Mathematics

2 answers:

Hunter-Best [27]3 years ago

8 0

Answer:

Today: Friday, 06 November 2020

Hour: 19.17 WIB (Indonesia)

_______________________________

2 (w + 3) = -2(w - 21)

2w + 6 = -2w + 42

2w + 2w = -6 + 42

4w = 36

w = 9

natta225 [31]3 years ago

3 0

Answer:

Step-by-step explanation:

2w+6=-2w+42

4w+6=42

4w=36

w=9

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Two trains leave towns 471 miles apart at the same time and travel toward each other. One train travels 21 miles per hour slower

nadya68 [22]

Let the slower train's velocity be x-21

Let the faster train's velocity be x

We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.

The approach rate is given by Distance/time = 471/3 = 157mpH

x+x-21=157

2x=157+21

2x=178

x=89mph

The slower train is travelling 89-21 = 68mph

The faster train is travelling 89mph.

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1 year ago

Nathan is building a toolshed with a rectangular floor. The area of a rectangle is given by the formula l⋅w, where l represents

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Answer:

L=7 and W=7 will have a larger floor

Step-by-step explanation:

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3 years ago

X² + 2x – 1 = 0 in English words.

Svet_ta [14]

Answer:

x squared plus two times x minus one = zero.

Step-by-step explanation:

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3 years ago

Read 2 more answers

Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are given the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

Finding  $\angle DFE$ :

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$

Finding  $\angle E$ :

Property of external angle: External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external $\angle DFG$ = $\angle E + \angle EDF$

$\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2} -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)$

Comparing equations (1) and (2):

It can be clearly seen that:

$\angle DFE = \angle E =90-\dfrac{y}{2}$

The two angles of $\triangle EDF$ are equal hence $\triangle EDF$ is isosceles.

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3 years ago

Solve for m and n using the special right triangles

Irina18 [472]

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