Answer:
8
Explanation:
What is the number of white blood cells permitted in a unit of leukoreduced red cells? 8 g/dL owing to chemotherapy with a drug known to cause bone marrow depression and immunodeficiency.
Answer:
When the flea bit someone, the <u><em>plague bacteria</em></u> would get transferred to that person.
<em>Hope this helps.</em>
Answer: Lymphatic tissues
Explanation: Lymphatic tissues have various distinct configurational groups correlated to its specific purpose in the resistance of a particular infection reaction. Lymphatic tissues can be primary or secondary in basic features, the primary lymphatic tissues in humans being thymus and bone marrow. However, the lymphocytes are shaped from a long thin corroborative section of cells in the soft fatty material in the compartments of bones in which cells are generated and then distributed in the lymphatic tissue.
Answer:
__ It implies that prokaryotes existed before eukaryotes, and
__ It implies that eukaryotes evolved from prokaryotes.
Explanation:
The prefix pro- can mean "before". By using the term prokaryote one can tend to think that procaryotes preceded eukaryotes.
Preceed as existed before them, or as an evolutionary point of view.
Answer:
The correct answer would be - MMR would be hindered because both strands would be unmethylated and both would appear as new DNA strands and it would not be able to determine which strand has the error
.
Explanation:
In gene expression or DNA replication, the enzyme responsible for the synthesis of DNA from nucleoside triphosphate causes errors sometimes such as mismatch base pair that result in a change in genetic makeup.
For MMR, the DNA template and the strand formed required easily to be differentiated. As the newly synthesized strand is unmethylated and the DNA template strand is methylated results in DNA remain hemimethylated for a very short period.
After MMR, DNA adenine methylase enzyme that transfers a methyl group to the adenine of the sequence 5'-GATC-3' daughter strand formed.
Mutated DAM or DNA adenine methylase will not be able to transfer methyl group which leaves both template and daughter strands unmethylated and mismatch repair would be hindered as it will not be able to identify.
