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3 years ago

True or false, when you reflect across the y-axis, the x-coordinate is multiplied by -1

Mathematics

1 answer:

kakasveta [241]3 years ago

6 0

Answer:

True

Step-by-step explanation:

The rule for reflecting over the y-axis is (-x,y)

If the coordinate was (3,2) the new coordinate would be (-3,2)

Hope this helps.

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For each of the following, use logic laws to decide whether the statement is a tautology contradiction, or neither. a (a) (A B)

spayn [35]

Answer:

The statement $(A\rightarrow \lnot B)\land (B\rightarrow A)$ is a contingency.

The statement $(P\rightarrow \lnot P)\land P$ is a contradiction.

Step-by-step explanation:

A tautology is a proposition that is always true.

A contradiction is a proposition that is always false.

A contingency is a proposition that is neither a tautology nor a contradiction.

a) To classify the statement $(A\rightarrow \lnot B)\land (B\rightarrow A)$ , you need to use the logic laws as follows:

$(A\rightarrow \lnot B)\land (B\rightarrow A) \equiv$

$\equiv (\lnot A \lor\lnot B)\land(\lnot B \lor A)$ by the logical equivalence involving conditional statement.

$\equiv (\lnot B\lor \lnot A )\land(\lnot B \lor A)$ by the Commutative law.

$\equiv \lnot B \lor (\lnot A \land A)$ by Distributive law.

$\equiv \lnot B \lor (A \land \lnot A)$ by the Commutative law.

$\equiv \lnot B \lor F$ by the Negation law.

Therefore the statement $(A\rightarrow \lnot B)\land (B\rightarrow A)$ is a contingency.

b) To classify the statement $(P\rightarrow \lnot P)\land P$ , you need to use the logic laws as follows:

$(P\rightarrow \lnot P)\land P \equiv$

$\equiv (\lnot P \lor \lnot P)\land P$ by the logical equivalence involving conditional statement.

$\equiv P \land (\lnot P \lor \lnot P)$ by the Commutative law.

$\equiv (P \land \lnot P) \lor (P \land \lnot P)$ by Distributive law.

$\equiv F \lor F \equiv F$ by the Negation law.

Therefore the statement $(P\rightarrow \lnot P)\land P$ is a contradiction.

8 0

3 years ago

A projectile is launched from ground level with a initial velocity of Vo feet per second. Neglecting air resistance, its height

antiseptic1488 [7]

The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.

Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s

The projectile reaches a height of 192 ft at 3 s on the way up, and at 4 s on the way down.

Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s

When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.

Answer: 7 s

4 0

3 years ago

Which ordered pair is not a point of the graph of y=1/2x-7

Tresset [83]

Where is the graph???

4 0

3 years ago

there are 3 second grade classes at the sunshine school one has 22students and another has 20 students if there are 63 students

alex41 [277]

there would be 21 in the last class

8 0

3 years ago

Read 2 more answers

I need help with number one and thank you for your help

sveta [45]

Answer: B

Step-by-step explanation: The first X was 1. If you add 1 too the 1/2 in the equation, its 1 & 1/2. theres only one graph that has 1 & 1/2, and its B

5 0

2 years ago

True or false, when you reflect across the y-axis, the x-coordinate is multiplied by -1​

True or false, when you reflect across the y-axis, the x-coordinate is multiplied by -1