1+sin²x=2-cos²x
Remenber: sin²x+cos²x=1 ⇒sin²x=1-cos²x
1+sin²x=1+(1-cos²x)=2-cos² x (this is true)
4x=-3y+17 becomes 4x+3y=17
4x+3y=17
3x-4y=-6
alrighty
elimination
muliply first equation by 4 and 2nd by 3 and add them
16x+12y=68
9x-12y=-18
add them
25x+0y=50
25x=50
idivide both sides by 25
x=2
sub back
3x-4y=-6
3(2)-4y=-6
6-4y=-6
-4y=-12
y=3
(x,y)
(2,3)
The side length is the square root of 8. Because the square has 4 equal sides, the side lengths must be equal. So the answer is approximately 2.83.
Answer:
An Isosceles Triangle
Step-by-step explanation:
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