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vampirchik [111]
3 years ago
10

HELP PLEASE!

Mathematics
2 answers:
masha68 [24]3 years ago
8 0

Answer:

5.0-2.5=2.5

Step-by-step explanation:

Bingel [31]3 years ago
4 0

Answer:

2.50 - 5.0= -2.50

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If Susie has 2 apples and she gave bill 1 how many apples does susie have?
Ludmilka [50]

Answer:

susie has 1 apple

7 0
3 years ago
Find the circumference and area of a circle with a diameter of 10 inches leave answers in terms of pi
Umnica [9.8K]

Answer:

The circumference is = 10π

The area is = 25π

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Numbers with the same absolute value are__________
Radda [10]
They are either the same, or opposite number.
4 0
4 years ago
Read 2 more answers
I need help asap :):)):
slega [8]

Answer:

Its to multiply the numerators by each other and the denominators by each other

Step-by-step explanation:

If adding and subtracting fractions is about finding the least common denominator

dividing fractions is to keep the first fraction,multiply and reverse the second fraction,so dividing is pretty similar to multiplying but just switching the divide sign with a multiplication sign and reversing the second fraction from numerator/denominator to denominator/numerator

and there is always a big difference if you multiply/divide or add/subtract

4 0
3 years ago
8. How many ways can a committee of 5 students be chosen from a student council of 30 students? Is the order in which the member
tankabanditka [31]

Answer: A committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

No , the order in which the members of the committee are chosen is not  important.

Step-by-step explanation:

Given : The total number of students in the council = 30

The number of students needed to be chosen = 5

The order in which the members of the committee are chosen does not matter.

So we Combinations (If order matters then we use permutations.)

The number of combinations of to select r things of n things = ^nC_r=\dfrac{n!}{r!(n-r)!}

So the number of ways a committee of 5 students can be chosen from a student council of 30 students=^{30}C_5=\dfrac{30!}{5!(30-5)!}

=\dfrac{30\times29\times28\times27\times26\times25!}{(120)\times25!}=142506

Therefore , a committee of 5 students can be chosen from a student council of 30 students in 142506 ways.

4 0
3 years ago
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