I would look through the numbers to determine their range. It appears to me to be 42 to 69. This suggests a frequency table with numbers 40 to 70, a range easily divided into 6 parts.
Since the width of each group will be (70 -40)/6 = 5, you have to decide on the group boundaries. It might work well to subtract 1/2 from the numbers 40, 45, 50, 55, 60, 65 to define the boundary. That way, for the integers given, you have
.. group 1 = 40 ≤ age < 45
.. group 2 = 45 ≤ age < 50
.. group 3 = 50 ≤ age < 55
.. group 4 = 55 ≤ age < 60
.. group 5 = 60 ≤ age < 65
.. group 6 = 65 ≤ age < 70
Answer:
(x-8y)(x-8y)
Step-by-step explanation:
write the expression as a product with the factors x and 8y
8^2 -2(x)8y+64y^2
multiply terms with equal exponents by multiplying the bases
x^2 -2 (x) 8y + (8y)^2
factor
(x-8y)^2 which is equal to c
To solve using synthetic division:
Draw an upside down division symbol (I did the best I can given the format). Place the constant of x - 1 (1) on the outside, and the coefficients of x³ - 2x² - 1 on the inside, like so:
| x³ x² x¹ x⁰
1 | 1 -2 0 -1
|
|___________
Next, bring down the first coefficient.
| x³ x² x¹ x⁰
1| 1 -2 0 -1
|
|___________
1
Multiply the number on the outside of the symbol (1) by the coefficient you've just brought down (1). Place that number under the next coefficient to the right.
| x³ x² x¹ x⁰
1| 1 -2 0 -1
| 1
|___________
1
Add the new number (1) to the coefficient above it (-2) and place that number directly underneath it.
| x³ x² x¹ x⁰
1| 1 -2 0 -1
| 1
|___________
1 -1
Continue this process until you've run out of numbers to multiply.
| x³ x² x¹ x⁰
1| 1 -2 0 -1
| 1 -1 -1
|___________
1 -1 -1 -2
The resulting numbers are coefficients. The first three are part of the quotient, and the last one is part of the remainder. The remainder becomes the last coefficient (-2) over the divisor (x - 1).
Answer:
(x³ - 2x² - 1) / (x - 1) = x² - x - 1 + -2/x - 1
Answer:
so I think its x=113
Step-by-step explanation:
alr so
180-67=113 so I think thats the answer id.k lol