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IRISSAK [1]
3 years ago
12

What point is on the graph of every direct variation equation. Plzzzz answer

Mathematics
2 answers:
vaieri [72.5K]3 years ago
6 0
  Direct variations are of the form y=kx
 For all values of k, when x= 0 y=0
Anettt [7]3 years ago
5 0
What does every Linear Equation have?
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Carlos Martin received a statement from his bank showing a balance of $56.75 as of March 15th his check book shows a balance of
kakasveta [241]

Answer:

$48.87

Step-by-step explanation:

Let the deposited amount between the March 15th and the March 20th be x

Balance on 15th march =  $56.75

The bank returned all the cancelled checks but too. One check was for $5 and the other was for $13.25

And he also deposited x amount

After deposits and deductions

So, balance = 56.75 +x - (13.25+5)

The new balance on 20th march =  $87.37

⇒56.75 +x - (13.25+5)=87.37

⇒56.75 +x - 18.25=87.37

⇒38.5 +x =87.37

⇒x =87.37-38.5

⇒x =48.87

Hence Carlos deposited  $48.87  in his account between the March 15th and the March 20th.

6 0
2 years ago
Read 2 more answers
What is the solution to the system of equations below?
Lilit [14]

Answer:

  x,y = -4, -15

Step-by-step explanation:

4 0
2 years ago
Given 4 c + 5 not-equals 0 and c is a real number, what is the multiplicative inverse of 4 c + 5 not-equals 0
Irina-Kira [14]

Answer:

1 / 4c+5

Step-by-step explanation:

Given :

4c + 5 ≠ 0

c is a real number.

Find the multiplicative inverse of equation ?

The multiplicative inverse of a number is reciprocal of number

Let

x = a number

The multiplicative inverse = 1/x

Let 4c + 5 ≠ 0 be a number x

Then, the multiplicative inverse of x = 1/x

x = 4c + 5

1/x = 1 / 4c+5

Therefore, the multiplicative inverse of 4c + 5 = 1 / 4c+5

7 0
2 years ago
Are these questions biased or not???​
o-na [289]

Answer:

No.

Step-by-step explanation:

Biased means extremely on one side, so no, the questions are not biased.

3 0
2 years ago
Read 2 more answers
How do I solve this out??
GuDViN [60]
<h3>Answer:</h3>

(x, y) = (7, -5)

<h3>Step-by-step explanation:</h3>

It generally works well to follow directions.

The matrix of coefficients is ...

\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]

Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...

\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]

So the solution is the product of this and the vector of constants [-6, -50]. That product is ...

... x = (3·(-6) +(-4)(-50))/26 = 7

... y = (5·(-6) +2·(-50))/26 = -5

The solution using inverse matrices is ...

... (x, y) = (7, -5)

7 0
2 years ago
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