I'LL GIVE BRAINLIEST

What is 8/40 in simplest form?

tensa zangetsu [6.8K]

Divide 8 by 8= 1
divide 40 by 8=5
1/5

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2 years ago

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What is the expanded from for 430,290,100

grin007 [14]

400,000,000 + 30,000,000 + 200,000 + 90,000 +100

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2 years ago

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1. Identify each situation in which a quantity grows or decays by a constant percent rate per unit interval. A. The number of ca

zvonat [6]

Answer:

Step-by-step explanation:

1) For each situation to grow or decay by a constant percent rate, it must be exponential. Therefore, the correct examples are

A. The number of cars sold doubles every year. It is a 200% growth every year.

D. Each time you start a car engine the remaining engine life decreases by 0.0075%. A case of decay

E. The number of people creating cat videos increases by 15% percent every year.

F. Computer technology increases by a factor of 3 every five years.

2) this is a case of exponential decay. The expression for exponential decay is

y = b(1 - r)^t

y = final value

b = initial value

r = decay rate

t = time

Given that

r = 10% = 10/100 = 0.1

b = 50 kilograms

y = W kilograms

The relationship is

W = 50(1 - 0.1)^t

W = 50(0.9)^t

3 0

2 years ago

Test scores of the student in a school are normally distributed mean 85 standard deviation 3 points. What's the probability that

Mrrafil [7]

Answer:

The probability that a random selected student score is greater than 76 is $\\ P(x>76) = 0.99865$ .

Step-by-step explanation:

The Normally distributed data are described by the normal distribution. This distribution is determined by two parameters, the population mean $\\ \mu$ and the population standard deviation $\\ \sigma$ .

To determine probabilities for the normal distribution, we can use the standard normal distribution, whose parameters' values are $\\ \mu = 0$ and $\\ \sigma = 1$ . However, we need to "transform" the raw score, in this case x = 76, to a z-score. To achieve this we use the next formula:

$\\ z = \frac{x - \mu}{\sigma}$ [1]

And for the latter, we have all the required information to obtain z. With this, we obtain a value that represent the distance from the population mean in standard deviations units.

<h3>The probability that a randomly selected student score is greater than 76</h3>

To obtain this probability, we can proceed as follows:

First: obtain the z-score for the raw score x = 76.

We know that:

$\\ \mu = 85$

$\\ \sigma = 3$

$\\ x = 76$

From equation [1], we have:

$\\ z = \frac{76 - 85}{3}$

Then

$\\ z = \frac{-9}{3}$

$\\ z = -3$

Second: Interpretation of the previous result.

In this case, the value is three (3) standard deviations below the population mean. In other words, the standard value for x = 76 is z = -3. So, we need to find P(x>76) or P(x>-3).

With this value of $\\ z = -3$ , we can obtain this probability consulting the cumulative standard normal distribution, available in any Statistics book or on the internet.

Third: Determination of the probability P(x>76) or P(x>-3).

Most of the time, the values for the cumulative standard normal distribution are for positive values of z. Fortunately, since the normal distributions are symmetrical, we can find the probability of a negative z having into account that (for this case):

$\\ P(z>-3) = 1 - P(z>3) = P(z$

Then

Consulting a cumulative standard normal table, we have that the cumulative probability for a value below than three (3) standard deviations is:

$\\ P(z$

Thus, "the probability that a random selected student score is greater than 76" for this case (that is, $\\ \mu = 85$ and $\\ \sigma = 3$ ) is $\\ P(x>76) = P(z>-3) = P(z$ .