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2 years ago

How to find the area of a dquare

Mathematics

2 answers:

Elena-2011 [213]2 years ago

4 0

Multiply one side by another

Gnesinka [82]2 years ago

3 0

Side times side
hope i can help u :)

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8n+16.2=1.6 what is n

creativ13 [48]

-1.825. you subtract 16.2 from 1.6. then divide that number by 8

5 0

3 years ago

Read 2 more answers

F(x)=8x^2-2x+3 g(x)=12x^2+4x-3 what is h(x)=f(x)-g(x)?

Trava [24]

Answer: $h(x)=-4x^2-6x+6$

Step-by-step explanation:

To find the function h(x), you need to subtract the function $f(x)=8x^2-2x+3$ and the function $g(x)=12x^2+4x-3$ .

$h(x)=f(x)-g(x)\\h(x)=8x^2-2x+3-(12x^2+4x-3)$

Distribute the negative sign:

$h(x)=8x^2-2x+3-12x^2-4x+3$

Now you can add the like terms:

$h(x)=-4x^2-6x+6$

Therefore, you get that the function h(x) is:

$h(x)=-4x^2-6x+6$

6 0

3 years ago

Read 2 more answers

Evaluate -(2^-6)(2^3) apex A.-1 over 8 B. -8 C.1 over 8 D.8

Andrews [41]

Answer:

option c is the correct answer.

5 0

2 years ago

Please help me Im confused on this problem

Sunny_sXe [5.5K]

Answer:

b = 6 sqrt(2)

Step-by-step explanation:

Since this is right triangle, we can use the Pythagorean theorem

a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse

3^2 + b^2 = 9^2

9+b^2 = 81

b^2 = 81-9

b^2 = 72

Take the square root of each side

sqrt(b^2) = sqrt(72)

b = sqrt(36*2)

b = 6 sqrt(2)

7 0

3 years ago

What is the remainder when (3x4 + 2x3 − x2 + 2x − 19) ÷ (x + 2)? 0 5 10 15

Elanso [62]

Answer: Second option is correct.

Explanation:

Since we have given that

$f(x)=3x^4+2x^3-x^2+2x-19$

And $g(x)=x+2$

To find the remainder, we use the Remainder Theorem, which states that when f(x) is divided by (x-c) then the f(c) is the required remainder.

So,

Here, we have,

$x+2=0\\\\x=-2$

So, we will find f(-2) which will give us the required remainder,

$f(-2)=3(-2)^4+2(-2)^3-(-2)^2+2(-2)-19\\\\f(-2)=(3\times 16)-(2\times 8)- 4-4-19\\\\f(-2)=48-16-36-4-19\\\\f(-2)=5$

Hence, Second option is correct.

7 0

2 years ago