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Agata [3.3K]
2 years ago
11

The amount of a chemical solution is measured to be 2 liters. What is the percent error of the measurement?

Mathematics
2 answers:
dezoksy [38]2 years ago
6 0
The complete question in the attached figure

we know that
2 liters may be 1.5 to 1.9 rounded up to 2
or 2.1 to 2.4 rounded down to 2

the biggest percent error would be between 2 and 1.5, which is a volume error of 0.5 liters
2 - 1.5 = 0.5 liters
percent error = (absolute error / quantity) * 100
percent error = [0.5/2] * 100% = 0.25 * 100% = 25%

the answer is the option C) 25%

Nadusha1986 [10]2 years ago
4 0

The amount of a chemical solution is measured to be 2 liters. What is the percent error of the measurement?

25%


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What ordered pair is a solution of the equation y-3=5(x-2)
RideAnS [48]

Answer:

(0,-7)

Step-by-step explanation:

In this question, we need to find an ordered pair of (x,y)  

First we need to solve the equation for Y. It will be:

y-3=5(x-2)  

y=5x-10 +3

y= 5x -7

Then, using the equation you can find the value of y using the value of x. If x= 0 the calculation will be

y= 5x-7

y= 5(0) - 7

y=-7

The ordered pair will be: (0,-7)

3 0
3 years ago
the only black pens and green pens in a box the ratio of a number of black pens in the box to the number of green pens in the bo
eduard

Fraction of black pens = 2/ (2 + 5)  = 2/7  answer

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3 years ago
WILL MARK BRAINLIST!! SOS MATH. Look at picture
Aleks [24]

Answer:

Yes, the transformation is a 270°  clockwise rotation

Step-by-step explanation:

(-3, 4) ,( -4, 7) and (-2,7) transformed to (-4, - 3), (-7, -4) and (-7, -2).

Rule for 270° clockwise rotation:

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3 years ago
A number doubled and has four added to it. The result is divided by three and then added to the product of the original number a
IrinaK [193]
X= a number

(2x+4)/3 + (x+2)= 20
Multiply everything by 3 to eliminate the fraction
(3/1)((2x+4)/3) + (3)(x+2)= (3)(20)
2x+4+3x+6= 60
5x+10=60
Subtract 10 from both sides
5x=50
divide both sides by 5
x=10

Check:
Substitute answer in original equation
(2x+4)/3 + (x+2)= 20
(2(10)+4)/3+(10+2)= 20
(20+4)/3+12= 20
24/3+12= 20
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Hope this helps! :)
8 0
3 years ago
Check whether the relation R on the set S = {1, 2, 3} is an equivalent
kozerog [31]

Answer:

R isn't an equivalence relation. It is reflexive but neither symmetric nor transitive.

Step-by-step explanation:

Let S denote a set of elements. S \times S would denote the set of all ordered pairs of elements of S\!.

For example, with S = \lbrace 1,\, 2,\, 3 \rbrace, (3,\, 2) and (2,\, 3) are both members of S \times S. However, (3,\, 2) \ne (2,\, 3) because the pairs are ordered.

A relation R on S\! is a subset of S \times S. For any two elementsa,\, b \in S, a \sim b if and only if the ordered pair (a,\, b) is in R\!.

 

A relation R on set S is an equivalence relation if it satisfies the following:

  • Reflexivity: for any a \in S, the relation R needs to ensure that a \sim a (that is: (a,\, a) \in R.)
  • Symmetry: for any a,\, b \in S, a \sim b if and only if b \sim a. In other words, either both (a,\, b) and (b,\, a) are in R, or neither is in R\!.
  • Transitivity: for any a,\, b,\, c \in S, if a \sim b and b \sim c, then a \sim c. In other words, if (a,\, b) and (b,\, c) are both in R, then (a,\, c) also needs to be in R\!.

The relation R (on S = \lbrace 1,\, 2,\, 3 \rbrace) in this question is indeed reflexive. (1,\, 1), (2,\, 2), and (3,\, 3) (one pair for each element of S) are all elements of R\!.

R isn't symmetric. (2,\, 3) \in R but (3,\, 2) \not \in R (the pairs in \! R are all ordered.) In other words, 3 isn't equivalent to 2 under R\! even though 2 \sim 3.

Neither is R transitive. (3,\, 1) \in R and (1,\, 2) \in R. However, (3,\, 2) \not \in R. In other words, under relation R\!, 3 \sim 1 and 1 \sim 2 does not imply 3 \sim 2.

3 0
3 years ago
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