Answer:
The distance is 1.41 to nearest hundredth.
Step-by-step explanation:
The line y = x + 3 passes through the point (0, 3) on the yaxis.
Find the perpendicular line passing through this point:
y - 3 = -1(x + 0)
y = -x + 3
Now find the point where this line intersects the line y = x + 1:
y = -x + 3
y = x + 1
-x + 3 = x + 1
3 -1 = x + x
2x = 2
x = 1
and y = 2
So this point is (1, 2)
We require the distance between this point and (0, 3)
This = √((3-2)^2 + (0-1)^2) = √2
= 1.4142
Option (A) : least: 10 hours; greatest: 14 hours
The function f(x) = sin x has all real numbers in its domain, but its range is
−1 ≤ sin x ≤ 1.
How to solve such range questions?
Such questions in which every term is in addition and its range is asked is simplest ones to solve if we know the range of each of term. This can be seen from this question
Given: d(t) = 2sin(xt) + 12
= −1 ≤ sin (xt) ≤ 1.
= −2≤ 2 sin (xt) ≤ 2.
= 10 ≤ 2sin (xt) + 12 ≤ 14
= 10 ≤d(t) ≤ 14
Thus least: 10 hours; greatest: 14 hours
Learn more about range of trigonometric ratios here :
brainly.com/question/14304883
#SPJ4
Your answer is 21 for this one.
Answer:
x = 6
Step-by-step explanation:
cross multiplication and a wild guess
Answer:
Answer B ![(-\infty,1)U(1,2]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C1%29U%281%2C2%5D)
Step-by-step explanation:
Notice that the quotient of f(x)/g(x) is:
therefore, this new function imposes conditions due to the fact that it has a square root in the numerator and a binomial in the denominator both with the variable x. Then, in order for the root in the numerator to be defined, the argument inside the root must be larger than or equal to zero. That is:
So, this condition must be satisfied by the x-values of the domain.
Then we have the binomial in the denominator, which in order to be defined needs to be different from zero. Notice that the only x-value that could cause problems (render zero) is:
Then, 
So we have to eliminate the number 1 from the previous subset that required x smaller than or equal to 2.
The way to represent this Domain is then:
