<span>625(5xy)^-3/ (5x)^2 y^7
625
= -------------------- / 25x^2y^7
125 x^3y^3
= 5/x^3y^3 / </span>25x^2y^7
= 5/x^3y^3 * (1/ 25x^2y^7)
= 1 / 5x^5y^10
answer
1
-----------------
5x^5y^10
You can turn 5 into 10/2 and add to x/2
then you need to use simple algebra to left the x alone in the equation so you need to multiply both sides by 2 so you get
2y=10+x
then you need to subtract both sides a 10 so
2y-10=x
now change the x to f'(x) and y to x so:
f'(x)=2x-10
Answer:
Step-by-step explanation:
n = 7 so it is:
5(7) - 4
= 35 - 4
= 31.
