Answer:
The ratio of the high-wire unicyclists to ball-balancing seals is;
Explanation:
Given that;
He has featured 32 high-wire unicyclists and 24 ball-balancing seals.
The ratio of the high-wire unicyclists to ball-balancing seals can be written as;
Reducing toits lowest form, we have;
divide both sides by 8;
Therefore, the ratio of the high-wire unicyclists to ball-balancing seals is;
Answer:
8
Step-by-step explanation:
To find the answer to these problems you can work backwards
12-4=8
Answer:
area= 604 cm^2
perimeter=376 cm
Step-by-step explanation:
radius(r)=28/2
=14 cm
<em>area of the semicircle</em>=2r*theta /360
=2*22/7*14*180/360
=44cm^2
<em>area of the rectangle</em>=l*b
=28*20
=560 cm^2
<em>total area</em>=semicircle area+rectangle area
=560+44
=<u>604 cm^2</u>
<em>arc length</em>=*theta/360
=22/7*14*14*180/360
=308cm^2
<em>perimeter</em>=28+20+308+20
=<u>376 cm</u>
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<em>Hope this helps you.</em>
Answer: At noon the temperature outside of Hector's home was 4 degree warmer than the temperature outside of gale's home.
Step-by-step explanation:
Here, x represents the number of hours after noon while g(x) and f(x) represents the temperature of gale's and hector's home respectively in x hours.
Since, at noon, x = 0
And, by the table g(x=0) = -1
That is, the temperature of gale's home is -1° F at noon.
And, by the given graph, f(x=0) = 3
That is, the the temperature of hector's home is 3° F at noon.
And, f(0)-g(0) = 3-(-1) = 4°F
That is, the difference between the temperature of hector's home at noon and the temperature of gale's home at noon is 4°F.
X = 1st number, y = 2nd number, z = 3rd number
x + y + z = 26
y = 2x
z = 2x + 6
x + (2x) + (2x + 6) = 26
5x + 6 = 26
5x = 26 - 6
5x = 20
x = 20/5
x = 4 <=== first number
y = 2x....y = 2(4) = 8 <=== second number
z = 2x + 6....z = 2(4) + 6 = 8 + 6 = 14 <=== third number