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3 years ago

How do I find the value of X

Mathematics

1 answer:

Simora [160]3 years ago

5 0

A^2 + b^2 = c^2
x^2 + 8^2 = 20^2
x^2 + 64 = 400
x^2 = 336
x = 4sqrt(21), or ~=~ 18.3303028

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F(x)=-x^2+3 find f(-2)

Luden [163]

Answer:

-1

Step-by-step explanation:

Replace x with -2

f(-2)=-(-2)^2+3

Solve.

f(-2)=-4+3

=-1

I hope this helps!

5 0

3 years ago

Read 2 more answers

Can someone help me this please

Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

$23=-6(-3)+c\\$ Plug in the given x- and y-coordinates (in this case we'll use $c$ for the missing variable)

$23=18+c$ Simplify

$5=c$ Subtract 18 from both sides (Subtraction Property of Equality)

8 0

4 years ago

-15p-16.5+30+4.5p. Need help

Ronch [10]

Steps to solve:

-15p - 16.5 + 30 + 4.5p

~Combine like terms

10.5p + 13.5

Best of Luck!

3 0

3 years ago

A. 12

kondor19780726 [428]

Tree casts a shadow 30 feet long. A MHS student standing near the tree casts a shadow 9 feet long. The student is 6 feet tall. What is the height of the tree? Show all work

Answer:

Option D

The height of tree is 20 feet tall

Solution:

From given question,

Shadow of tree = 30 feet

Height of tree = ?

Height of student = 6 feet

Shadow of student = 9 feet

We have to find the height of tree

We can solve the sum by proportion

$\frac{\text{height of tree}}{\text{shadow of tree}} = \frac{\text{height of student}}{\text{shadow of tree}}$

This forms a proportion and we can solve the sum by cross multiplying

$\frac{\text{height of tree}}{30} = \frac{6}{9}\\\\\text{height of tree} = 30 \times \frac{6}{9} = 30 \times \frac{2}{3}\\\\\text{ height of tree } = 10 \times 2 = 20$