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3 years ago

How many whole numders have the sum of 40

Mathematics

1 answer:

cluponka [151]3 years ago

6 0

Answer:

We start with 0 + 40.

1. 0 + 40

2. 1 + 39

3. 2 + 38

4. 3 + 37

.....

keep going....

.....

19. 18 + 22

20. 19 + 21

21. 20 + 20

There are 21 pairs of whole numbers that have a sum of 40.

Step-by-step explanation:

hope this helps :)

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Choose the domain for which each function is defined

klemol [59]

Answer:

Part 1) $f(x)=\frac{x+4}{x}$ -----> $x\neq 0$

Part 2) $f(x)=\frac{x}{x+4}$ ----> $x\neq -4$

Part 3) $f(x)=x(x+4)$ ----> All real numbers

Part 4) $f(x)=\frac{4}{x^2+8x+16}$ ----> $x\neq -4$

Step-by-step explanation:

we know that

The domain of a function is the set of all possible values of x

Part 1) we have

$f(x)=\frac{x+4}{x}$

we know that

In a quotient the denominator cannot be equal to zero

For the value of x=0 the function is not defined

therefore

The domain is

$x\neq 0$

Part 2) we have

$f(x)=\frac{x}{x+4}$

we know that

In a quotient the denominator cannot be equal to zero

For the value of x=-4 the function is not defined

therefore

The domain is

$x\neq -4$

Part 3) we have

$f(x)=x(x+4)$

Applying the distributive property

$f*(x)=x^2+4x$

This is a vertical parabola open upward

The function is defined by all the values of x

therefore

The domain is all real numbers

Part 4) we have

$f(x)=\frac{4}{x^2+8x+16}$

we know that

In a quotient the denominator cannot be equal to zero

Equate the denominator to zero

$x^2+8x+16=0$

Remember that

$x^2+8x+16=(x+4)^2$

( $x+4)^2=0$

The solution is x=-4

For the value of x=-4 the function is not defined

therefore

The domain is

$x\neq -4$

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Answer:

$(-5,-4)$

Step-by-step explanation:

A 180 counterclockwise rotation of (5, 4).

The transformation rule is as follows:

$(x,y)$ turns into $(-x,-y)$ .

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