PLEASE HELP ME! :) A) A B) B C) C D) D

In which pair of numbers is the first number of the multiple of the second number?

irina1246 [14]

Your answer would be c. 18,6

7 0

2 years ago

A tablet computer costs $189.69 including tax. It is marked up 30%.

Alina [70]

The correct answer is D. $246.6
(It is actually $246.597 but that is rounded to 246.6)
$189.69 x .3 = 56.907
$189.69 + $56.907 = $246.597

3 0

3 years ago

Read 2 more answers

Sketch the algebra-tile shape at right on your paper. Write an expression for the

Dima020 [189]

Answer:

Part 1) $P=(4x+4)\ units$

Part 2)

a) $P=32\ units$

b) $P=26\ units$

c) $P=13\frac{1}{3}\ units$

Step-by-step explanation:

The complete question in the attached figure

Part 1) Write an expression for the perimeter of the shape

we know that

The figure is composed by a larger square, a rectangle and a smaller square

1) The area of the larger square is given

$A=x^2\ units^2$

so

The length and the width of the larger square is x units

2) The area of the rectangle is given

$A=x\ units^2$

so

The length of the rectangle is x units and the width is 1 unit

3) The length and the width of the smaller square is x units

see the attached figure N 2 to better understand the problem

Find out the perimeter

The perimeter is the sum of all the sides.

so

$P=(x+x+x+x+1+1+1+1)$

$P=(4x+4)\ units$

Part 2) Find the perimeter for each of the given values of x.

a) For x=7 units

Substitute the value of x in the expression of the perimeter

$P=(4(7)+4)=32\ units$

b) For x=5.5 units

Substitute the value of x in the expression of the perimeter

$P=(4(5.5)+4)=26\ units$

b) For x=7/3 units

Substitute the value of x in the expression of the perimeter

$P=(4(\frac{7}{3})+4)=\frac{40}{3}=13\frac{1}{3}\ units$

8 0

3 years ago

Factor 4a^2-25. Please

Dmitrij [34]

Answer:

(2 a - 5) (2 a + 5)

Step-by-step explanation:

Factor the following:

4 a^2 - 25

4 a^2 - 25 = (2 a)^2 - 5^2:

(2 a)^2 - 5^2

Factor the difference of two squares. (2 a)^2 - 5^2 = (2 a - 5) (2 a + 5):

Answer: (2 a - 5) (2 a + 5)

8 0

2 years ago

find real numbers a, b, and c so that the graph of the function y=ax^2+c contains the points (-1,6), (2,7), and (0,1)

Paraphin [41]

This gives you three simultaneous equations:

6 = a + c
7 = 4a + c
1 = c

c = 1

If c =1,

6 = a + 1
a = 5

This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?

5 0

3 years ago