Answer:
Note: The full question is attached as picture below
a) Hо : p = 0.71
Ha : p ≠ 0.71
<em>p </em>= x / n
<em>p </em>= 91/110
<em>p </em>= 0.83.
1 - Pо = 1 - 0.71 = 0.29.
b) Test statistic = z
= <em>p </em>- Pо / [√Pо * (1 - Pо ) / n]
= 0.83 - 0.71 / [√(0.71 * 0.29) / 110]
= 0.12 / 0.043265
= 2.77360453
Test statistic = 2.77
c) P-value
P(z > 2.77) = 2 * [1 - P(z < 2.77)] = 2 * 0.0028
P-value = 0.0056
∝ = 0.01
P-value < ∝
Reject the null hypothesis. There is sufficient evidence to support the researchers claim at the 1% significance level.
The answer is B. Complete information.
A sample means only part of the whole. From the day the email was created till it was cancelled is the whole population. Consider that no mails will no longer go in because it is closed so no more additional information or data will enter that category. So it would be considered as complete. If the situation were to ask from one point to another before it was cancelled it would be considered as a sample.
Answer:
It's C! 75%
Step-by-step explanation:
Writing the problem as an equation you have:
2x+6 > -16
Solve for x:
2x+6 > -16
Subtract 6 from each side:
2x > -22
Divide both sides by 2:
x > -11
The answer is: x > -11
In order to solve the amount of each solution, we need to set up equations. We do as follows:
Let x = solution with 32% sodium
y = solution with 12% sodium
Overall balance
x + y = 50
Component balance
.32x + .12y = 50(.20) =10
Solving simultaneously,
x = 20
y = 30
Hope this answers the question. Have a nice day.
