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OlgaM077 [116]
3 years ago
7

90 • 4 – 14 ÷ 2 + 102 ÷ 5 • 2

Mathematics
2 answers:
sveta [45]3 years ago
8 0
90*4-14/2+102/5*2

360-7+40,8

393,8
liraira [26]3 years ago
3 0
You would have to do
P-Parenthesis
E- exponents
M- multiplication
D- division
A- addition
S-subtraction

Follow those steps and you'll get it
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D/5 = 4 please explain I do not get this. Thank you
MAXImum [283]
<span>D/5 = 4
Multiply 5 on both sides
Final Answer: D = 20</span>
8 0
3 years ago
A circle has a sector with area 33 pi and a central angle of 11/6 pi radians. What is the area of a circle?
Mashutka [201]

Answer:

36π

Step-by-step explanation:

The area of a circle is given as:

A = \pi r^2

where r = radius of the circle

The area of a sector of a circle is given as:

A_s = \frac{\alpha }{2\pi} * \pi r^2

where α = central angle in radians

Since \pi r^2 is the area of a circle, A, this implies that:

A_s = \frac{\alpha }{360}  * A

A circle has a sector with area 33 pi and a central angle of 11/6 pi radians.

Therefore, the area of the circle, A, is:

33 \pi = \frac{\frac{11 \pi}{6} }{2 \pi} * A\\\\33\pi = \frac{11}{12} * A\\\\=> A = \frac{33\pi * 12}{11}\\ \\A = \frac{396 \pi}{11} \\\\A = 36\pi

The area of the circle is 36π.

5 0
3 years ago
Read 2 more answers
Is this graph Proportioal or Not Proportional?
Over [174]

Answer:

Proportioal

Step-by-step explanation:

?

3 0
3 years ago
Luis is saving up to buy a new phone. He already has $25 and can save an additional $6 per week using money from his after schoo
sdas [7]

Answer:

$85

Step-by-step explanation:

he would have $85 bc if u save 6 per week for 10 weeks that 60 yk so then 60 pu 25 is 85 not that hard tbh

3 0
2 years ago
Read 2 more answers
What is the limit of f (×) as x approaches - infinty
tatyana61 [14]
If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the leading coefficient of denominator.

So then the limit would be 3/1 = 3.

Alternatively,

\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}=\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}\cdot\dfrac{1/x^2}{1/x^2}=\lim_{x\to\infty}\dfrac{3+\frac6{x^2}}{1-\frac4{x^2}} = \dfrac{3+0}{1-0}=\boxed{3}

Hope this helps.
5 0
3 years ago
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