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Dvinal [7]
3 years ago
5

. Each U.S. coin is mapped to its monetary value. Tell whether this situation represents a function. Explain your reasoning. If

the situation represents a function, give the domain and range.
Mathematics
1 answer:
xxTIMURxx [149]3 years ago
8 0
Coin       Value

cent              1 cent         
nickel           5 cents
dime           10 cents
quarter        25 cents
dollar        100 cents

This is a function, because you can state unambiguosly the value of each  coin.

The domain is the set of input values: { cent, nickel, dime, quarter, dollar}

The range is the set of output values: {1, 5, 10, 25, 100}


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16/(q+1)=4
16/(q+1)=4 > Mult. both sides by (q+1)
16=4q+4 > Subtract 4 from both sides.
12=4q > Div. both sides by 4
q=3

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At a particular restaurant, 62% of all customers order an appetizer and 41% of all customers order dessert. If 69% of all custom
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Answer:

In terms of probablity (A - appetizer oredered, B - desert ordered)

P(A)=63%

P(B)=40%

P(AorB)=76%.

Using the formula:

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Answer:

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

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In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

In the study 340 babies were​ born, and 289 of them were girls. This means that n = 340, \pi = \frac{289}{340} = 0.85

Use the sample data to construct a 99​% confidence interval estimate of the percentage of girls born.

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 - 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.80

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 + 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.90

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

Does the method appear to be ​effective?

b)Yes, the proportion of girls is significantly different from 0.5.

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