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MrMuchimi
3 years ago
5

Work your brain today y'all!! I had $3.00. My Mom gave me $10.00. My Dad Gave me $30.00. My Aunt & Uncle gave me $100.00. I

had another $7.00. How much did I have? Right answer will get deleted. I won against: Kelli Kimber
Mathematics
1 answer:
bonufazy [111]3 years ago
8 0

Answer:

$10

Step-by-step explanation:

The question made is How much did I have? This question is about the amount of money that you had before receiving the money from your mom, dad and aunt and uncle. This means that the answer is the $3 you had plus the other $7 you said you had. So, $3+$7=$10. You had $10.

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jason mixed 8ml of a salt solution with 11ml of a 47% salt solution to make a 43%salt solution. find the percent salt concentrat
choli [55]

Let x% be the salt concentration of first solution.

Then in 8ml, amount of salt = \frac{8x}{100}

Given that to this 8ml solution, 11ml solution of a 47% salt solution is mixed.

amount of salt in 11ml of 47% salt solution is \frac{11*47}{100} = \frac{517}{100}

So, total amount of salt in new mixture = \frac{8x}{100} +\frac{517}{100} = \frac{8x+517}{100}

But given that this new solution is a 43% salt solution.

Hence amount of salt in new mixture of (8+11)=19ml solution of 43% salt solution is \frac{19*43}{100} = \frac{817}{100}

Hence \frac{8x+517}{100} = \frac{817}{100}

            8x+517 = 817

             8x=817-517 = 300

          x= 300/8 = 37.5

Hence the salt concentration in the first solution is 37.5%

8 0
3 years ago
Plz help ;-; I think its B...
SVETLANKA909090 [29]

Answer:

its C it has 4

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which trigonometric ratios are correct for triangle ABC?
kykrilka [37]

Answer:

c

Step-by-step explanation:

4 0
3 years ago
Solve the system of equations.
guajiro [1.7K]

Answer:

<u>Option b. (x = 3, y = 20, z = -14)</u>

Step-by-step explanation:

Given:

2x + 2y + 3z = 4

5x + 3y + 5z = 5

3x + 4y + 6z = 5

Solve using Cramer’s rule

∴ \left[\begin{array}{ccc}2&2&3\\5&3&5\\3&4&6\end{array}\right] =\left[\begin{array}{ccc}4\\5\\5\end{array}\right]

∴A = \left[\begin{array}{ccc}2&2&3\\5&3&5\\3&4&6\end{array}\right] = -1

Ax = \left[\begin{array}{ccc}4&2&3\\5&3&5\\5&4&6\end{array}\right] = -3

Ay = \left[\begin{array}{ccc}2&4&3\\5&5&5\\3&5&6\end{array}\right] =-20\\

Az = \left[\begin{array}{ccc}2&2&4\\5&3&5\\3&4&5\end{array}\right] = 14

∴ x = Ax/A = -3/-1 = 3

   y = Ay/A = -20/-1 = 20

   z = Az/A = 14/-1 = -14

<u>So, the answer is option b. (x = 3, y = 20, z = -14)</u>

4 0
3 years ago
Find three consecutive even integers such that 3 times the first is 26 less than twice the sum of the last two
Dimas [21]
Let's say our first integer is "a".

how to get the next consecutive EVEN integer?  well, just add or subtract 2 from it, therefore, the second consecutive integer will be "a + 2".

and the next after that, will then be (a + 2) + 2, or "a + 4".

so those are are 3 integers, a           a + 2           a+4

notice that, from any even or odd integer, if you hop twice either forwards or backwards, you'll land on another even or odd integer respectively.

2 + 2 is 4, or 8 + 2 is 10  some even ones

3 + 2 is 5, or 13 + 2 is 15, some odd ones

\bf \stackrel{\textit{3 times the first}}{3a}~~=~~\stackrel{\textit{26 less than twice the sum of the others}}{2[~(a+2)+(a+4)~]~~~-26}&#10;\\\\\\&#10;3a=2[~2a+6~]-26\implies 3a=4a+12-26\implies 3a=4a-14&#10;\\\\\\&#10;0=a-14\implies 14=a

what are the other two consecutive integers?  well, a + 2 and a + 4.
4 0
3 years ago
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