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MrMuchimi
2 years ago
5

Work your brain today y'all!! I had $3.00. My Mom gave me $10.00. My Dad Gave me $30.00. My Aunt & Uncle gave me $100.00. I

had another $7.00. How much did I have? Right answer will get deleted. I won against: Kelli Kimber
Mathematics
1 answer:
bonufazy [111]2 years ago
8 0

Answer:

$10

Step-by-step explanation:

The question made is How much did I have? This question is about the amount of money that you had before receiving the money from your mom, dad and aunt and uncle. This means that the answer is the $3 you had plus the other $7 you said you had. So, $3+$7=$10. You had $10.

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Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!
IgorC [24]
Hey there, hope I can help!

-4x^2+9y^2+32x+36y-64=0

\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \  9y^2+32x+36y-4x^2=64

\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \  -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4
-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9
-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}

\mathrm{Convert}\:x\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert}\:y\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \  -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1

Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1

For me I used
\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1
As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1

Hope this helps!
4 0
3 years ago
От
enot [183]

Answer:

2.75 miles, 14520 feet

Step-by-step explanation:

11 miles/4=2.75

1 mile=5280 feet

2.75 miles=14520 feet

6 0
2 years ago
**HELP!**
mr_godi [17]
If two figures or lengths are similar, then the ratios of the corresponding lengths are equal.
Thus, 8/32 =5/x
          8x = 160
            x = 20 feet
Therefore, the length of the flag pole was 20 feet long
3 0
2 years ago
Which of the following numbers has a value that is between 10% and 1/9? (a) 0.151 (b) 0.112 (c) 0.108 (d) 0.019
Westkost [7]
First you have to change each one into a decimal.

10% = 0.10
1/9 = 0.11

So the answer has to be between 0.10 and 0.11.

A is more than 0.11.
B is more than 0.11.
C is between 0.10 and 0.11.
D is less than 0.10.

The answer is C. 0.108.
6 0
3 years ago
Dan has 4 groups of 10 and 3 left over.
Alexxx [7]
Is there anything else? Like what is the question asking?
3 0
3 years ago
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