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Leona [35]
3 years ago
6

12 oz for $1.39 or 14 oz for $1.49

Mathematics
1 answer:
Inessa05 [86]3 years ago
4 0
<span> <span><span> <span> The shared variance is (coefficient of determination) is .36. </span> </span> </span></span>
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Uninhibited growth can be modeled by exponential functions other than​ A(t) ​=Upper A 0 e Superscript kt. For ​ example, if an i
laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than A(t)=A_{0}e^{kt}. for example, if an initial population P₀ requires n units of time to triple, then the function P(t)=P_{0}(3)^{\frac{t}{n} } models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form P(t)=P_{0}(3)^{\frac{t}{n} } that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form A(t)=A_{0}e^{kt}.

Answer: a) P(t)=50(3)^{\frac{t}{30} }

              b) P(t) = 280 insects

              c) t = 74 days

             d) A(t)=50e^{0.037t}

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

P(t)=50(3)^{\frac{t}{30} }

b) In t = 47 days:

P(t)=50(3)^{\frac{t}{30} }

P(47)=50(3)^{\frac{47}{30} }

P(47)=50(3)^{1.567}

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

750=50(3)^{\frac{t}{30} }

\frac{750}{50}=(3)^{\frac{t}{30} }

(3)^{\frac{t}{n} }=15

Using the property <u>Power</u> <u>Rule</u> of logarithm:

log(3)^{\frac{t}{30} }=log15

\frac{t}{30}log(3)=log15

t=\frac{log15}{log3} .30

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

A(t)=A_{0}e^{kt}

3A_{0}=A_{0}e^{30k}

3=e^{30k}

Use Power Rule again:

ln3=ln(e^{30k})

ln3=30k

k=\frac{ln3}{30}

k = 0.037

Equation for exponential growth will be:

A(t)=50e^{0.037t}

3 0
2 years ago
Please help will mark brainliest
IRINA_888 [86]

Answer:

It’s either A or C

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Need this ASAP please help
Amanda [17]

Answer:

Step-by-step explanation:

b

7 0
2 years ago
Read 2 more answers
Which expression is equivalent to 6(4v)?
riadik2000 [5.3K]

Answer:

24v

Step-by-step explanation:

simply multiply perform the distributive property. so multiply 6 and 4 and you should get 24. after just add in the v.

pls mark brainlest

5 0
2 years ago
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Help plsplsplsplsplsplspls
MatroZZZ [7]

Answer:

48-20x=21

Step-by-step explanation:

So, we basically have to clear the fractions (get rid of the denominators)

Multiply everything by the LCM of 6 and 8 (24)

24(2)-24(5/6x)=24(7/8)

48-20x=21

Hope this helps!

6 0
3 years ago
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