A third of a shipment of books is 28 pounds. <u>Assuming that 'f' will be the total weight of the entire shipment,</u> we would divide 'f' by 3 to get 28.

The answer should be D.

3 0

3 years ago

What is the constant of 6y=8x?

notka56 [123]

Answer:

-40

Step-by-step explanation:

multiplie then go your self cause you mdkdj you cant do math hahahhaha

4 0

3 years ago

Two trees are in a garden. The 20-foot tree casts a shadow four feet long. If the other tree is 15-foot tall, how long will its

Kobotan [32]

They are similar triangles so 20/4=15/x
solve for x
20x=15*4=60
x=3

4 0

4 years ago

Read 2 more answers

The coordinates of the vertices of triangle ABC are A(3,6), B(6, 3), and C(9, 9). If triangle ABC Is dilated by 1/3x and 1/3y to

katovenus [111]

Answer:

$A' = (1,2)$

$B'=(2,1)$

$C' =(3,3)$

Step-by-step explanation:

Given

$A = (3,6)$

$B = (6,3)$

$C = (9,9)$

$Scale = \frac{1}{3}$

Required

Determine the vertices of ABC

If truly the question asks for the vertices of ABC, then the vertices are:

$A = (3,6)$ $B = (6,3)$ $C = (9,9)$

However, I'm quite sure that's not the requirement of the question. So, I'll solve for A'B'C'

To do this, we simply multiply the vertices of ABC by the scale of dilation.

$(A'B'C') = Scale\ Factor * (ABC)$

$A' = \frac{1}{3} * A$

$A' = \frac{1}{3} * (3,6)$

$A' = (\frac{3}{3},\frac{6}{3})$

$A' = (1,2)$

$B' = \frac{1}{3} * B$

$B' = \frac{1}{3} * (6,3)$

$B' = (\frac{6}{3},\frac{3}{3})$

$B'=(2,1)$

$C' = \frac{1}{3} * C$

$C' = \frac{1}{3} * (9,9)$

$C' = (\frac{9}{3},\frac{9}{3})$

$C' =(3,3)$

6 0

3 years ago